在非活动类中使用 getResources() [英] Using getResources() in non-activity class

问题描述

我正在尝试在非活动类中使用 getResources 方法.如何获取对资源"对象的引用，以便我可以访问存储在资源文件夹下的 xml 文件?

I am trying to use getResources method in a non-activity class. How do I get the reference to the "resources" object so that I can access the xml file stored under resources folder?

示例:

XmlPullParser xpp = getResources().getXml(R.xml.samplexml);

推荐答案

您必须将 context 对象传递给它.this 如果您在活动中有对类的引用，或者 getApplicationContext()

You will have to pass a context object to it. Either this if you have a reference to the class in an activty, or getApplicationContext()

public class MyActivity extends Activity {
    public void onCreate(Bundle savedInstanceState) {
        RegularClass regularClass = new RegularClass(this);
    }
}

然后就可以在构造函数中使用(或者设置为实例变量):

Then you can use it in the constructor (or set it to an instance variable):

public class RegularClass(){
    private Context context;

    public RegularClass(Context current){
        this.context = current;
    }

    public findResource(){
        context.getResources().getXml(R.xml.samplexml);
    }
}

构造函数接受Context作为参数的地方

Where the constructor accepts Context as a parameter

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