在 ActionBar 中有两个单选组不起作用，但附加弹出菜单也不起作用 [英] Having two single-selection groups in ActionBar doesn't work, but attaching a pop up menu instead doesn't work either

问题描述

我正在编写一个 Android 应用程序，用户必须在其中选择在图表上显示的方式和内容.这些选项以两个单选菜单组(单选按钮)表示，这两个菜单组都应该可以从操作栏访问.

I am writing an Android app where the user must choose how and what to display on a graph. These options are expressed in two single-selection menu groups (radio buttons), both of which should be accessible from the action bar.

第一组工作正常.它添加在我的 ActionBar XML 的末尾，如下所示:

The first group works fine. It's added at the end of my ActionBar XML like this:

<group android:checkableBehavior="single" android:showAsAction="never" >
    <item android:id="@+id/menu_choice_1" android:title="Choice 1" />
    <item android:id="@+id/menu_choice_2" android:title="Choice 2" android:checked="true"/>
</group>

当我在第一个下面添加第二个 时，这两个合并到一个单选列表中.换句话说，两个列表中的选项会一起呈现，如果我选择第一个列表的选项，则无法从第二个列表中选择任何选项.

When I add a second <group> below the first one, however, the two merge into one single-selection list. In other words, the options from both lists are rendered together and if I choose an option pertaining to the first list, I cannot choose anything from the second.

相反，我想要两个单独的列表单选按钮.我的下一个想法是在 ActionBar 中添加另一个按钮，当点击该按钮时，它会启动一个 弹出菜单.但是当我点击按钮时，我得到一个 IllegalStateException，说我的没有锚点就不能使用 MenuPopupHelper".

Instead, I want two separate lists of radio buttons. My next idea was to add another button the ActionBar that, when clicked, would launch a pop-up menu. But when I click the button, I get an IllegalStateException, saying that my "MenuPopupHelper cannot be used without an anchor".

这是我尝试的弹出菜单代码:

Here is my attempted pop-up menu code:

在我的 ActionBar XML 中:

In my ActionBar XML:

<item android:id="@+id/menu_openothermenu"
  android:title="@string/openothermenustr"
  android:showAsAction="always" />

我的新菜单 XML:

<?xml version="1.0" encoding="utf-8"?>
<menu xmlns:android="http://schemas.android.com/apk/res/android">
    <group android:checkableBehavior="single">
        <item android:id="@+id/menu_2_choice_1" android:title="@string/2_choice_1" />
        <item android:id="@+id/menu_2_choice_2" android:title="@string/2_choice_2" android:checked="true"/>
    </group>
</menu>

我的活动中的代码:

@Override
public boolean onOptionsItemSelected(MenuItem item) {
    SharedPreferences settings = getSharedPreferences(PREFS_NAME, 0);
    SharedPreferences.Editor editor;

    switch (item.getItemId()) {
    case R.id.openothermenu:
        Menu m = (Menu) findViewById(R.menu.other_menu);
        PopupMenu popup = new PopupMenu(this, findViewById(R.menu.main_menu));
        popup.setOnMenuItemClickListener(this);
        MenuInflater inflater = popup.getMenuInflater();
        inflater.inflate(R.menu.other_menu, popup.getMenu());
        /* This commented block doesn't work either, and prevents execution
        // Restore saved chosen value
        int chosen = settings.getInt(MENU_2_PREFS, -1);
        switch(chosen)
        {
            case 1:
                m.findItem(R.id.menu_1_choice_1).setChecked(true);
                updateVisibleThings();
                break;
            default:
            case 2:
                m.findItem(R.id.menu_2_choice_2).setChecked(true);
                updateOtherVisibleThings();
                break;
        }
        */
        popup.show();
        return true;
    default:
        return super.onOptionsItemSelected(item);
    }
}

@Override
public boolean onMenuItemClick(MenuItem item) {
    SharedPreferences settings = getSharedPreferences(PREFS_NAME, 0);
    SharedPreferences.Editor editor;

    switch(item.getItemId()) {
    case R.id.menu_2_choice_1:
        if (item.isChecked()) item.setChecked(false);
        else item.setChecked(true);
        updateVisibleThings();

        // save chosen setting
        editor = settings.edit();
        editor.putInt(MENU_2_PREFS, 1);
        editor.commit(); // Commit the edits!

        return true;
    case R.id.menu_2_choice_2:
        if (item.isChecked()) item.setChecked(false);
        else item.setChecked(true);
        updateOtherVisibleThings();

        // save chosen setting
        editor = settings.edit();
        editor.putInt(MENU_2_PREFS, 2);
        editor.commit(); // Commit the edits!

        return true;
    default:
        return true;
    }
}

如何创建两组可检查的菜单项，使它们都附加到 ActionBar?

推荐答案

我找到了一种优雅的方法来解决这个问题，但不幸的是文档中没有.将以下代码添加到您的 ActionBar 菜单 XML:

I found an elegant way to solve this that was unfortunately not in the documentation. Add the following code to your ActionBar menu XML:

<item android:id="@+id/menu_openothermenu"
      android:title="@string/openothermenustr"
      android:showAsAction="always">
    <menu>
        <group android:checkableBehavior="single">
            <item android:id="@+id/menu_2_choice_1" android:title="@string/2_choice_1"  android:showAsAction="never" />
            <item android:id="@+id/menu_2_choice_2" android:title="@string/2_choice_2"  android:showAsAction="never" android:checked="true" />
        </group>
     </menu>
</item>

显示这样的菜单不需要额外的处理程序代码或弹出菜单实现.

No extra handler code or popup menu implementation is necessary for such a menu to appear.

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