如何在 Android XML DOM Parsing 中解析同名标签? [英] How to parse same name tag in Android XML DOM Parsing?

问题描述

我无法在这里解析我的 XML.它返回项目"只有.
我的 AndroidActivity 无法显示，因为它非常大.这就是为什么我只展示了负责解析的部分.

I am not able to parse my XML here. It returns "Item" only.
My AndroidActivity cannot be shown as it is very big. That's why I have only shown the part which is responsible for parsing.

我的 XML 如下所示:

My XML Looks like this :

<MyResource>
<Item>First</Item>
<Item>Second</Item>
</MyResource>

我的 ActivityClass 方法:

My ActivityClass method:

public class ShowItems extends Activity{
    ListView lv;
    ListAdapter adapter;
    static final String KEY_RESOURCE = "MyResource"; // parent node 
    static final String KEY_ITEM = "Item";
    ArrayList<HashMap<String, String>> mylist = new ArrayList<HashMap<String, String>>();
    String[] from={KEY_ITEM };
    int[] to={R.id.mylist_item};
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        // TODO Auto-generated method stub
        super.onCreate(savedInstanceState);
        setContentView(R.layout.showitems);
        
        lv=(ListView) findViewById(R.id.lv_items);
        parseXML();
        adapter = new SimpleAdapter(this, mylist,R.layout.list_item,from , to); 
        lv.setAdapter(adapter);
    }

private void parseXML() {
    // TODO Auto-generated method stub
    XMLParser parser = new XMLParser();
    
    final String URL="http://10.0.2.2:8080/MySite/xml";
    String xml = parser.getXmlFromUrl(URL); 
    Document doc = parser.getDomElement(xml); 
    NodeList nl = doc.getElementsByTagName(KEY_RESOURCE); 
    for (int i = 0; i < nl.getLength(); i++) {

        HashMap<String, String> map = new HashMap<String, String>();
        Element e = (Element) nl.item(i); 
        map.put(KEY_ITEM, parser.getValue(e, KEY_ITEM)); 
        mylist.add(map); }
}

我的 XML 解析器类:

My XML Parser Class:

import java.io.IOException;
import java.io.StringReader;
import java.io.UnsupportedEncodingException;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.util.EntityUtils;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.InputSource;
import org.xml.sax.SAXException;
import android.util.Log;
public class XMLParser {
    public String getXmlFromUrl(String url) { 
        String xml = null; 
        try { 
            HttpClient httpClient = new DefaultHttpClient();
            HttpGet httpGet = new HttpGet(url);
            HttpResponse httpResponse = httpClient.execute(httpGet);
            HttpEntity httpEntity = httpResponse.getEntity(); 
            xml = EntityUtils.toString(httpEntity); 
        } catch (UnsupportedEncodingException e) { 
            e.printStackTrace(); 
        } catch (ClientProtocolException e) { 
            e.printStackTrace(); 
        } catch (IOException e) { 
            e.printStackTrace(); 
        } 
        return xml; 
    }
    
    public Document getDomElement(String xml){ 
        Document doc = null; 
        DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); 
        try { 
            DocumentBuilder db = dbf.newDocumentBuilder(); 
            InputSource is = new InputSource(); 
                is.setCharacterStream(new StringReader(xml)); 
                doc = db.parse(is);  
            } catch (ParserConfigurationException e) { 
                Log.e("Error: ", e.getMessage()); 
                return null; 
            } catch (SAXException e) { 
                Log.e("Error: ", e.getMessage()); 
                return null; 
            } catch (IOException e) { 
                Log.e("Error: ", e.getMessage()); 
                return null; 
            } 
                // return DOM 
            return doc; 
    }
    
    public String getValue(Element item, String str) {       
        NodeList n = item.getElementsByTagName(str);         
        return this.getElementValue(n.item(0)); 
    } 
    public final String getElementValue( Node elem ) { 
             Node child; 
             if( elem != null){ 
                 if (elem.hasChildNodes()){ 
                     for( child = elem.getFirstChild(); child != null; child = child.getNextSibling() ){ 
                         if( child.getNodeType() == Node.TEXT_NODE  ){ 
                             return child.getNodeValue(); 
                         } 
                     } 
                 } 
             } 
             return ""; 
      } 
}

我无法在这里解析我的 XML.这里有什么问题?
它返回项目"只有.
我需要在我的 ActivityClass 中做什么，尤其是在这部分代码中?

I am not able to parse my XML here. What is the problem here?
It returns "Item" only.
What do I need to do in my ActivityClass especially in this part of the code?

String xml = parser.getXmlFromUrl(URL); 
    Document doc = parser.getDomElement(xml); 
    NodeList nl = doc.getElementsByTagName(KEY_RESOURCE); 
    for (int i = 0; i < nl.getLength(); i++) {
        
        
        HashMap<String, String> map = new HashMap<String, String>();
        Element e = (Element) nl.item(i); 
        map.put(KEY_ITEM, parser.getValue(e, KEY_ITEM)); 
        mylist.add(map); }

推荐答案

你的 getValue() 方法获取 MyResource 元素，从那里，你需要获取下的所有 ItemsMyResource 并执行 getElementValue().示例代码是:

Your getValue() method gets MyResource element, from there, you need to get all Items under MyResource and do getElementValue(). Example code is:

   public Map getValue(Element item, String str) {
        NodeList n = item.getElementsByTagName(str);
        for (int i = 0; i < n.getLength(); i++) {
            System.out.println(getElementValue(n.item(i)));
        }
        //Here store it in list/map and return list/map instead of String
        return list/MapHere;
    }

这篇关于如何在 Android XML DOM Parsing 中解析同名标签?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！