变量不会从 AJAX 函数返回 [英] Variable doesn't get returned from AJAX function

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本文介绍了变量不会从 AJAX 函数返回的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

随着我的框架的增长,我决定将其拆分为多个文件,而不是将其留在主设计文件中.但是,通过这样做,函数的返回不会返回任何值.

As my framework grows i decided to split it into files, instead of leaving it in the main design file. However by doing that the return of a function doesn't return any value.

数据不为空 - 如果我提醒 js 文件中的值,它们就在那里!

data isn't empty - if i alert the values in the js file they are there!

功能:

1st .js 文件中的函数(在执行前包含)

1st the function in .js file (is included before the execution)

             var lock_get = 0;
             function get_data(data, destination) 
             {

                if (lock_get == 0)
                {
                    lock_get = 1;
                    $.ajax({
                        type: "POST",
                        url: destination,
                        async: true,
                        data: data,
                        success: function(data) 
                        {
                            lock_get = 0;
                            if (data)
                            {
                                return data;
                            }
                        }
                    });
                }
             };

所以,这里是执行部分:

So and here is the execution part:

    var test = get_data(data, destination);
    notice(test);

并且测试是空的......我已经尝试了不同的写作方式,但我想我误解了js的可能性?

and test is empty... I already tried different ways for writing but I guess i missunderstood the possibilities of js?

推荐答案

你不能这样做:由于调用是异步的,get_data 函数无法返回 ajax 调用的结果.

You can't do that : as the call is asynchronous, the get_data function can't return the result of the ajax call.

您应该做的是向 get_data 函数提供回调并在回调中处理结果.

What you should do is provide a callback to the get_data function and handle the result in the callback.

function get_data(data, destination, callback) 
         {

            if (lock_get == 0)
            {
                lock_get = 1;
                $.ajax({
                    type: "POST",
                    url: destination,
                    async: true,
                    data: data,
                    success: function(data) 
                    {
                        lock_get = 0;
                        if (data && callback)
                        {
                            callback(data);
                        }
                    }
                });
            }
         };

然后这样称呼它:

get_data(data, destination, function(test){
   notice(test);
});

这篇关于变量不会从 AJAX 函数返回的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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