向除发送者以外的所有客户端发送响应 [英] Send response to all clients except sender

问题描述

要向所有客户端发送内容，请使用:

To send something to all clients, you use:

io.sockets.emit('response', data);

要从客户那里接收信息，您可以使用:

To receive from clients, you use:

socket.on('cursor', function(data) {
  ...
});

如何将两者结合起来，以便在服务器上从客户端接收消息时，将该消息发送给除发送消息的用户之外的所有用户?

How can I combine the two so that when recieving a message on the server from a client, I send that message to all users except the one sending the message?

socket.on('cursor', function(data) {
  io.sockets.emit('response', data);
});

我是否必须通过发送带有消息的客户端 ID 然后在客户端检查来破解它，还是有更简单的方法?

Do I have to hack it around by sending the client-id with the message and then checking on the client-side or is there an easier way?

推荐答案

这是我的列表(更新为 1.0):

// sending to sender-client only
socket.emit('message', "this is a test");

// sending to all clients, include sender
io.emit('message', "this is a test");

// sending to all clients except sender
socket.broadcast.emit('message', "this is a test");

// sending to all clients in 'game' room(channel) except sender
socket.broadcast.to('game').emit('message', 'nice game');

// sending to all clients in 'game' room(channel), include sender
io.in('game').emit('message', 'cool game');

// sending to sender client, only if they are in 'game' room(channel)
socket.to('game').emit('message', 'enjoy the game');

// sending to all clients in namespace 'myNamespace', include sender
io.of('myNamespace').emit('message', 'gg');

// sending to individual socketid
socket.broadcast.to(socketid).emit('message', 'for your eyes only');

// list socketid
for (var socketid in io.sockets.sockets) {}
 OR
Object.keys(io.sockets.sockets).forEach((socketid) => {});

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