如何将 JSON 数据转换为 Python 对象? [英] How to convert JSON data into a Python object?

问题描述

我想将 JSON 数据转换为 Python 对象.

I want to convert JSON data into a Python object.

我从 Facebook API 接收 JSON 数据对象，我想将其存储在我的数据库中.

I receive JSON data objects from the Facebook API, which I want to store in my database.

我在 Django (Python) 中的当前视图(request.POST 包含 JSON):

My current View in Django (Python) (request.POST contains the JSON):

response = request.POST
user = FbApiUser(user_id = response['id'])
user.name = response['name']
user.username = response['username']
user.save()

• 这很好用，但我如何处理复杂的 JSON 数据对象?
• 如果我能以某种方式将此 JSON 对象转换为 Python 对象以便于使用，岂不是更好?

推荐答案

你可以试试这个:

class User(object):
    def __init__(self, name, username):
        self.name = name
        self.username = username

import json
j = json.loads(your_json)
u = User(**j)

只需创建一个新对象，并将参数作为映射传递即可.

Just create a new object, and pass the parameters as a map.

注意:它不适用于嵌套类.

Note: It does not work for nested classes.

您也可以使用带有对象的 JSON:

You can have a JSON with objects too:

import json
class Address(object):
    def __init__(self, street, number):
        self.street = street
        self.number = number

    def __str__(self):
        return "{0} {1}".format(self.street, self.number)

class User(object):
    def __init__(self, name, address):
        self.name = name
        self.address = Address(**address)

    def __str__(self):
        return "{0} ,{1}".format(self.name, self.address)

if __name__ == '__main__':
    js = '''{"name":"Cristian", "address":{"street":"Sesame","number":122}}'''
    j = json.loads(js)
    print(j)
    u = User(**j)
    print(u)

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