使用 json_decode 在 PHP 中解析 JSON 对象 [英] Parsing JSON object in PHP using json_decode

问题描述

我尝试从以 JSON 格式提供数据的 Web 服务请求天气.我没有成功的 PHP 请求代码是:

I tried to request the weather from a web service supplying data in JSON format. My PHP request code, which did not succeed was:

$url="http://www.worldweatheronline.com/feed/weather.ashx?q=schruns,austria&format=json&num_of_days=5&key=8f2d1ea151085304102710";
$json = file_get_contents($url);
$data = json_decode($json, TRUE);
echo $data[0]->weather->weatherIconUrl[0]->value;    

这是返回的一些数据.为简洁起见，部分细节已被截断，但保留了对象完整性:

This is some of the data that was returned. Some of the details have been truncated for brevity, but object integrity is retained:

{ "data": 
    { "current_condition": 
        [ { "cloudcover": "31",
            ... } ],  
      "request": 
        [ { "query": "Schruns, Austria",
            "type": "City" } ],
      "weather": 
        [ { "date": "2010-10-27",
            "precipMM": "0.0",
            "tempMaxC": "3",
            "tempMaxF": "38",
            "tempMinC": "-13",
            "tempMinF": "9",
            "weatherCode": "113",
            "weatherDesc": [ {"value": "Sunny" } ],
            "weatherIconUrl": [ {"value": "http://www.worldweatheronline.com/images/wsymbols01_png_64/wsymbol_0001_sunny.png" } ],
            "winddir16Point": "N",
            "winddirDegree": "356",
            "winddirection": "N",
            "windspeedKmph": "5",
            "windspeedMiles": "3" }, 
          { "date": "2010-10-28",
            ... },

          ... ]
        }
    }
}

推荐答案

这似乎有效:

$url = 'http://www.worldweatheronline.com/feed/weather.ashx?q=schruns,austria&format=json&num_of_days=5&key=8f2d1ea151085304102710%22';
$content = file_get_contents($url);
$json = json_decode($content, true);

foreach($json['data']['weather'] as $item) {
    print $item['date'];
    print ' - ';
    print $item['weatherDesc'][0]['value'];
    print ' - ';
    print '<img src="' . $item['weatherIconUrl'][0]['value'] . '" border="0" alt="" />';
    print '<br>';
}

如果将 json_decode 的第二个参数设置为 true，则会得到一个数组，因此不能使用 -> 语法.我还建议您安装 JSONview Firefox 扩展，因此您可以在类似于 Firefox 显示 XML 结构的格式良好的树视图中查看生成的 json 文档.这让事情变得容易多了.

If you set the second parameter of json_decode to true, you get an array, so you cant use the -> syntax. I would also suggest you install the JSONview Firefox extension, so you can view generated json documents in a nice formatted tree view similiar to how Firefox displays XML structures. This makes things a lot easier.

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