如何在不重复之前的随机数的情况下在 Swift 中生成随机数? [英] How to generate a random number in Swift without repeating the previous random number?

问题描述

我对 Swift 和编程逻辑还很陌生，请耐心等待

I'm pretty new to Swift and programming logic in general so bear with me

如何在 Swift 中生成 0 到 9 之间的随机数而不重复上次生成的数字?因为同一个数字不会连续出现两次.

How can you generate a random number between 0 and 9 in Swift without repeating the last generated number? As in the same number won't come up twice in a row.

推荐答案

将之前生成的数字存储在一个变量中，并将生成的数字与之前的数字进行比较.如果它们匹配生成一个新的随机数.重复生成新数字，直到它们不匹配为止.

Store the previous generated number in a variable and compare the generated number to the previous number. If they match generate a new random number. Repeat the generation of new numbers until they don't match.

var previousNumber: UInt32? // used in randomNumber() 

func randomNumber() -> UInt32 {
    var randomNumber = arc4random_uniform(10)
    while previousNumber == randomNumber {
        randomNumber = arc4random_uniform(10)
    }
    previousNumber = randomNumber
    return randomNumber
}

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