从 Python 迭代器获取最后一项的最简洁方法 [英] Cleanest way to get last item from Python iterator

问题描述

从 Python 2.6 中的迭代器获取最后一项的最佳方法是什么?例如，说

What's the best way of getting the last item from an iterator in Python 2.6? For example, say

my_iter = iter(range(5))

从 my_iter 获取 4 的最短代码/最干净的方法是什么?

What is the shortest-code / cleanest way of getting 4 from my_iter?

我可以这样做，但似乎效率不高:

I could do this, but it doesn't seem very efficient:

[x for x in my_iter][-1]

推荐答案

item = defaultvalue
for item in my_iter:
    pass

这篇关于从 Python 迭代器获取最后一项的最简洁方法的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！