如何在时间间隔后显示图像? [英] How to display an image after a time interval?
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问题描述
我想在用户单击鼠标左键 3 秒后显示图像.这是我的代码的一部分:
I want to display an image 3 seconds after the user has clicked the left mouse button. Here's a part of my code:
pic=pygame.image.load('pic.png')
while True:
for event.type==pygame.MOUSEBUTTONDOWN:
screen.blit(pic,(100,100))
它只显示片刻.我尝试使用 for
和 while
循环,但是,它会断断续续几秒钟,然后显示一个闪光.
It is only displayed a moment. I tried using for
and while
loops, however, it stutters some seconds and then shows a flash.
我想我可以使用计时器,添加 3 秒,如下所示:
I think that I can maybe use a timer, add 3s, like so:
for event.type==pygame.MOUSEBUTTONDOWN:
#get now time here,and assignment for timeclick
if timeclick+3s>=timenow: # pseudocode
screen.blit(pic,(100,100))
我该如何编写这段代码?还有更好的方法吗?
How can I write this code paragraph? And are there better ways?
推荐答案
当用户点击鼠标按钮时启动计时器,然后在主循环中计算经过的时间,如果>= 3
, blit 图像.
Start the timer when the user clicks a mouse button, then calculate the passed time in the main loop and if it's >= 3
, blit the image.
import pygame as pg
def main():
screen = pg.display.set_mode((640, 480))
clock = pg.time.Clock()
font = pg.font.Font(None, 40)
img = pg.Surface((100, 100))
img.fill((190, 140, 50))
click_time = 0
passed_time = 0
done = False
while not done:
for event in pg.event.get():
if event.type == pg.QUIT:
done = True
# Start the timer.
elif event.type == pg.MOUSEBUTTONDOWN:
click_time = pg.time.get_ticks()
screen.fill((30, 30, 30))
if click_time != 0: # If timer has been started.
# Calculate the passed time since the click.
passed_time = (pg.time.get_ticks()-click_time) / 1000
# If 3 seconds have passed, blit the image.
if passed_time >= 3:
screen.blit(img, (50, 70))
txt = font.render(str(passed_time), True, (80, 150, 200))
screen.blit(txt, (50, 20))
pg.display.flip()
clock.tick(30)
if __name__ == '__main__':
pg.init()
main()
pg.quit()
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