Ruby 中的排序是否稳定? [英] Is sort in Ruby stable?
问题描述
sort
在 Ruby 中稳定吗?也就是说,对于 sort
并列的元素,它们之间的相对顺序是否保留了原始顺序?例如,给定:
a = [{id: :a, int: 3},{id: :b, 整数: 1},{id: :c, int: 2},{id: :d, int: 0},{id: :e, 整数: 1},{id: :f, int: 0},{id::g, int: 1},{id: :h, int: 2},]
是否保证我们总是得到
a.sort_by{|h|暗示]}
以下
<预><代码>[{id: :d, int: 0},{id: :f, int: 0},{id: :b, 整数: 1},{id: :e, 整数: 1},{id::g, int: 1},{id: :c, int: 2},{id: :h, int: 2},{id: :a, int: 3},]:id
值为 :d
、:f
和 的元素之间的相对顺序没有任何变化:b
、:e
、:g
,还有:c
、:h
?如果是这种情况,在文档中的哪个位置对其进行了描述?
这个问题可能与这个问题有关,也可能没有.
Both MRIsort 和 sort_by 是 不稳定.前段时间有一个请求让它们稳定,但被拒绝了.原因:Ruby 使用就地快速排序算法,如果不需要稳定性,它的性能会更好.请注意,您仍然可以从不稳定的方法中实现稳定的方法:
module 可枚举def stable_sortsort_by.with_index { |x, idx|[x, idx] }结尾def stable_sort_bysort_by.with_index { |x, idx|[产量(x), idx] }结尾结尾
Is sort
in Ruby stable? That is, for elements that are in a tie for sort
, is the relative order among them preserved from the original order? For example, given:
a = [
{id: :a, int: 3},
{id: :b, int: 1},
{id: :c, int: 2},
{id: :d, int: 0},
{id: :e, int: 1},
{id: :f, int: 0},
{id: :g, int: 1},
{id: :h, int: 2},
]
is it guaranteed that we always get for
a.sort_by{|h| h[:int]}
the following
[
{id: :d, int: 0},
{id: :f, int: 0},
{id: :b, int: 1},
{id: :e, int: 1},
{id: :g, int: 1},
{id: :c, int: 2},
{id: :h, int: 2},
{id: :a, int: 3},
]
without any variation for the relative order among the elements with the :id
value :d
, :f
, and among :b
, :e
, :g
, and among :c
, :h
? If that is the case, where in the documentation is it described?
This question may or may not have connection with this question.
Both MRI's sort and sort_by are unstable. Some time ago there was a request to make them stable, but it was rejected. The reason: Ruby uses an in-place quicksort algorithm, which performs better if stability is not required. Note that you can still implement stable methods from unstable ones:
module Enumerable
def stable_sort
sort_by.with_index { |x, idx| [x, idx] }
end
def stable_sort_by
sort_by.with_index { |x, idx| [yield(x), idx] }
end
end
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