通过 AJAX 请求根据用户输入重新绘制谷歌图表 [英] Redraw google chart based on user input via AJAX request

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本文介绍了通过 AJAX 请求根据用户输入重新绘制谷歌图表的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我有一个从我的数据库中提取数据的谷歌图表，它可以按我的意愿工作.根据 URL 中的 get 请求，它从所选表中提取数据.

I have a google chart pulling data from my database that works as I want it to. Based on a get request in the URL it draws the data from the selected table.

我想根据从下拉菜单中选择的表格通过 ajax 更新此图表.我无法突破的部分是通过 ajax 使数据具有响应性.我认为下面的代码很接近，但我遇到了以下错误，我似乎无法摆脱.

I want make this chart update via ajax based on a selected table from a drop down menu. The part I can't break through on is getting the data to be responsive via ajax. I think the below code is close, but I'm getting the below error that I can't seem to get rid of.

getdata.php:22 Uncaught ReferenceError: $ is not defineddrawVisualization @getdata.php:22onchange @getdata.php:47

getdata.php:22 Uncaught ReferenceError: $ is not defineddrawVisualization @ getdata.php:22onchange @ getdata.php:47

我尝试从 getdata.php 中删除 GET 请求并硬编码一个表，认为这是 $not 定义，但这并没有解决错误.

I tried removing the GET request from the getdata.php and hard coding a table in thinking that was the $not defined, but that didn't resolve the error.

工作图代码

<!DOCTYPE>
<html>
<head> 
<meta http-equiv="content-type" content="text/html; charset=utf-8"/>
<title>
Wind Graph
</title>
<script type="text/javascript" src="http://www.google.com/jsapi"></script>
<script type="text/javascript">
google.load('visualization', '1', {packages: ['corechart']});
</script>
<script type="text/javascript">

function drawVisualization() {

var data = new google.visualization.DataTable();

<?php
require("dbconnect.php");

echo " data.addColumn('string', 'Time');";
echo " data.addColumn('number', 'Wind_Speed');";
echo " data.addColumn('number', 'Wind_Gust');";

$db = mysql_connect($server, $user_name, $password);
mysql_select_db($database);

$sqlQuery = "SELECT * FROM ".$_GET['q']." WHERE Date(Time + INTERVAL 10 HOUR) = Date(UTC_TIMESTAMP() + INTERVAL 10 HOUR)";
$sqlResult = mysql_query($sqlQuery);
while ($row = mysql_fetch_assoc($sqlResult)) {

echo " data.addRow(['{$row['Time']}', {v: {$row['Wind_Speed']}, f: '{$row['Wind_Speed']}' }, {v: {$row['Wind_Gust']}, f: '{$row['Wind_Gust']}' } ]); ";

}

?>

// Create and draw the visualization.
new google.visualization.LineChart(document.getElementById('visualization')).
draw(data, {curveType: "none",
title: "AU0001 Wind Chart",
titleTextStyle: {color: "orange"},
//width: 800, height: 400,
//vAxis: {maxValue: 10},
vAxis: {minValue: 0},
vAxis: {title: 'Wind Speed (Knots)'},
vAxis: {baseline: 0},
vAxis: {gridlines: {count: 10}  },
vAxis: {title: "Wind Speed (Knots)", titleTextStyle: {color: "orange"}},
hAxis: {title: "Time", titleTextStyle: {color: "orange"}},
interpolateNulls: 1
}
);
}

google.setOnLoadCallback(drawVisualization);
</script>
</head>
<body>
<div id="visualization" style="width: 100%; height: 400px;"></div>
</body>
</html>

带有 AJAX 请求的新代码

<!DOCTYPE>
<html>
<head> 
<meta http-equiv="content-type" content="text/html; charset=utf-8"/>
<title>
Wind Graph
</title>
<script type="text/javascript" src="http://www.google.com/jsapi"></script>
<script type="text/javascript">
google.load('visualization', '1', {packages: ['corechart']});
</script>
<script type="text/javascript">

function drawVisualization(num) {

var data = new google.visualization.DataTable(TableData);
var TableData = $.ajax({
  url: "getdata.php",
  data: "q="+num,
  dataType:"json",
  async: false
}).responseText;

// Create and draw the visualization.
new google.visualization.LineChart(document.getElementById('visualization')).
draw(data, {curveType: "none",
title: "Wind Chart",
titleTextStyle: {color: "orange"},
//width: 800, height: 400,
//vAxis: {maxValue: 10},
vAxis: {minValue: 0},
vAxis: {title: 'Wind Speed (Knots)'},
vAxis: {baseline: 0},
vAxis: {gridlines: {count: 10}  },
vAxis: {title: "Wind Speed (Knots)", titleTextStyle: {color: "orange"}},
hAxis: {title: "Time", titleTextStyle: {color: "orange"}},
interpolateNulls: 1
}
);
}

//  google.setOnLoadCallback(drawVisualization);
</script>
</head>
<body style="font-family: Arial;border: 0 none;">
<form>
<select name="users" onchange="drawVisualization(this.value)">
<option value="">Select unit:</option>
<option value="0001">0001</option>
<option value="0002">0002</option>

</select>
</form>
<div id="visualization" style="width: 100%; height: 400px;"></div>
</body>
</html>

getdata.php 代码

<?php
require("dbconnect.php");

echo " data.addColumn('string', 'Time');";
echo " data.addColumn('number', 'Wind_Speed');";
echo " data.addColumn('number', 'Wind_Gust');";

$db = mysql_connect($server, $user_name, $password);
mysql_select_db($database);


$sqlQuery = "SELECT * FROM ".$_GET['q']." WHERE Date(Time + INTERVAL 10 HOUR) = Date(UTC_TIMESTAMP() + INTERVAL 10 HOUR)";
$sqlResult = mysql_query($sqlQuery);
while ($row = mysql_fetch_assoc($sqlResult)) {

echo " data.addRow(['{$row['Time']}', {v: {$row['Wind_Speed']}, f: '{$row['Wind_Speed']}' }, {v: {$row['Wind_Gust']}, f: '{$row['Wind_Gust']}' } ]); ";

}

?>

推荐答案

推荐使用php获取google接受形式的json

recommend using php to get json in the form that google accepts

以下是使用ajax从php获取json数据并绘制谷歌图表的完整示例

php 

<?php
  require("dbconnect.php");

  $db = mysql_connect($server, $user_name, $password);
  mysql_select_db($database);

  $sqlQuery = "SELECT * FROM ".$_GET['q']." WHERE Date(Time + INTERVAL 10 HOUR) = Date(UTC_TIMESTAMP() + INTERVAL 10 HOUR)";
  $sqlResult = mysql_query($sqlQuery);

  $rows = array();
  $table = array();

  $table['cols'] = array(
      array('label' => 'Time', 'type' => 'string'),
      array('label' => 'Wind_Speed', 'type' => 'number'),
      array('label' => 'Wind_Gust', 'type' => 'number')
  );

  while ($row = mysql_fetch_assoc($sqlResult)) {
    $temp = array();
    $temp[] = array('v' => (string) $row['Time']);
    $temp[] = array('v' => (float) $row['Wind_Speed']);
    $temp[] = array('v' => (float) $row['Wind_Gust']);
    $rows[] = array('c' => $temp);
  }

  $table['rows'] = $rows;

  echo json_encode($table);
?>

并且不推荐使用--> async: false
或内联事件处理程序 -->

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