Ajax 将数据传递给 php 脚本 [英] Ajax passing data to php script

问题描述

我正在尝试将数据发送到我的 PHP 脚本以处理一些内容并生成一些项目.

I am trying to send data to my PHP script to handle some stuff and generate some items.

$.ajax({  
    type: "POST",  
    url: "test.php", 
    data: "album="+ this.title,
    success: function(response) {
        content.html(response);
    }
});

在我的 PHP 文件中，我尝试检索专辑名称.虽然当我验证它时，我创建了一个警报来显示 albumname 是什么我什么也没得到，我尝试通过 $albumname = $_GET['album'];

In my PHP file I try to retrieve the album name. Though when I validate it, I created an alert to show what the albumname is I get nothing, I try to get the album name by $albumname = $_GET['album'];

虽然它会说 undefined :/

Though it will say undefined :/

推荐答案

您正在发送 POST AJAX 请求，因此在您的服务器上使用 $albumname = $_POST['album']; 来获取价值.此外，我建议您编写这样的请求以确保正确编码:

You are sending a POST AJAX request so use $albumname = $_POST['album']; on your server to fetch the value. Also I would recommend you writing the request like this in order to ensure proper encoding:

$.ajax({  
    type: 'POST',  
    url: 'test.php', 
    data: { album: this.title },
    success: function(response) {
        content.html(response);
    }
});

或其较短的形式:

$.post('test.php', { album: this.title }, function() {
    content.html(response);
});

如果您想使用 GET 请求:

and if you wanted to use a GET request:

$.ajax({  
    type: 'GET',
    url: 'test.php', 
    data: { album: this.title },
    success: function(response) {
        content.html(response);
    }
});

或其较短的形式:

$.get('test.php', { album: this.title }, function() {
    content.html(response);
});

现在你可以在你的服务器上使用 $albumname = $_GET['album'];.但是要小心使用 AJAX GET 请求，因为它们可能会被某些浏览器缓存.为了避免缓存它们，您可以设置 cache: false 设置.

and now on your server you wil be able to use $albumname = $_GET['album'];. Be careful though with AJAX GET requests as they might be cached by some browsers. To avoid caching them you could set the cache: false setting.

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