如何在 Bash/Grep 中转义单引号? [英] How to escape single quotes in Bash/Grep?

问题描述

我想用 grep 搜索如下所示的字符串:

I want to search with grep for a string that looks like this:

something ~* 'bla'

我试过这个，但是shell删除了单引号argh..

I tried this, but the shell removes the single quotes argh..

grep -i '"something ~* '[:alnum:]'"' /var/log/syslog

什么是正确的搜索?

推荐答案

grep -i "something ~* '[[:alnum:]]*'" /var/log/syslog

对我有用.

• 转义第一个 * 以匹配文字 * 而不是使其成为零个或多个匹配字符:
  ~* 将匹配零次或多次出现的 ~ 而
  ~* 匹配 something
之后的表达式 ~*
• 在 :alnum: 周围使用双括号(参见示例 这里)
• 在 [[:alnum::]] 之后使用 * 不仅可以匹配单引号之间的 一个 字符，还可以匹配其中的几个
• 单引号根本不需要转义，因为它们包含在受双引号限制的表达式中.

• escape the first * to match a literal * instead of making it the zero-or-more-matches character:
  ~* would match zero or more occurrences of ~ while
  ~* matches the expression ~* after something
• use double brackets around :alnum: (see example here)
• use a * after [[:alnum::]] to match not only one character between your single quotes but several of them
• the single quotes don't have to be escaped at all because they are contained in an expression that is limited by double quotes.

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