根据 OP 的评论，SearchCriterionModel 将包含多个具有验证属性的属性，然后方法是包含一个提交按钮并处理表单 .submit() 事件
var url = '@Url.Action("DisplaySearchResults", "Search")';$('form').submit(function() {如果 (!$(this).valid()) {返回假；//如果验证错误，则阻止 ajax 调用}var form = $(this).serialize();$('#searchResults').load(url, form);返回假；//阻止默认提交动作})
控制器方法是
public ActionResult DisplaySearchResults(SearchCriterionModel 标准){var model =//根据标准的属性构建列表返回 PartialView("SearchResults", 模型);}
The problem I will be describing is very similar to ones I already found (e.g. this post with nearly identical name) but I hope that I can make it into something that is not a duplicate.
I have created a new ASP.NET MVC 5 application in Visual Studio. Then, I defined two model classes:
public class SearchCriterionModel
{
public string Keyword { get; set; }
}
public class SearchResultModel
{
public int Id { get; set; }
public string FirstName { get; set; }
public string Surname { get; set; }
}
Then I created the SearchController as follows:
public class SearchController : Controller
{
public ActionResult Index()
{
return View();
}
public ActionResult DisplaySearchResults()
{
var model = new List<SearchResultModel>
{
new SearchResultModel { Id=1, FirstName="Peter", Surname="Pan" },
new SearchResultModel { Id=2, FirstName="Jane", Surname="Doe" }
};
return PartialView("SearchResults", model);
}
}
as well as views Index.cshtml (strongly typed with SearchCriterionModel as model and template Edit) and SearchResults.cshtml as a partial view with model of type IEnumerable<SearchResultModel> (template List).
As you can see, I added a div with id="searchResults" below the standard template and edited the button. What I want is to display the partial view SearchResults.cshtml in the div on the bottom, but only after the button is clicked. I have succeeded in showing a partial view there by using @Html.Partial("SearchResults", ViewBag.MyData), but it is rendered when the parent view is loaded for the first time and I set ViewBag.MyData in the Index() method already, which is not what I want.
Summary: On clicking the button, I will obtain some List of SearchResultModel instances (via database access) and then the partial view should be rendered, using this newly obtained data as model. How can I accomplish this? I already seem fail at the first step, that is reacting to the button click with the above code. Right now, I navigate to the URL ~/Search/DisplaySearchResults, but of course there's nothing there and no code-behind method is called.
In traditional ASP.NET I'd just have added a server-side OnClick handler, set the DataSource for a grid and show the grid. But in MVC I already fail with this simple task...
Update: Changing the button to @Html.ActionLink I can finally enter the controller method. But naturally since it returns the partial view, it's displayed as the whole page content. So the question is: How do I tell the partial view to be rendered inside a specific div on the client side?
解决方案
Change the button to
<button id="search">Search</button>
and add the following script
var url = '@Url.Action("DisplaySearchResults", "Search")';
$('#search').click(function() {
var keyWord = $('#Keyword').val();
$('#searchResults').load(url, { searchText: keyWord });
})
and modify the controller method to accept the search text
public ActionResult DisplaySearchResults(string searchText)
{
var model = // build list based on parameter searchText
return PartialView("SearchResults", model);
}
The jQuery .load method calls your controller method, passing the value of the search text and updates the contents of the <div> with the partial view.
Side note: The use of a <form> tag and @Html.ValidationSummary() and @Html.ValidationMessageFor() are probably not necessary here. Your never returning the Index view so ValidationSummary makes no sense and I assume you want a null search text to return all results, and in any case you do not have any validation attributes for property Keyword so there is nothing to validate.
Edit
Based on OP's comments that SearchCriterionModel will contain multiple properties with validation attributes, then the approach would be to include a submit button and handle the forms .submit() event
<input type="submit" value="Search" />
var url = '@Url.Action("DisplaySearchResults", "Search")';
$('form').submit(function() {
if (!$(this).valid()) {
return false; // prevent the ajax call if validation errors
}
var form = $(this).serialize();
$('#searchResults').load(url, form);
return false; // prevent the default submit action
})
and the controller method would be
public ActionResult DisplaySearchResults(SearchCriterionModel criteria)
{
var model = // build list based on the properties of criteria
return PartialView("SearchResults", model);
}
这篇关于在 ASP.NET MVC 中单击按钮时呈现局部视图的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
