在 JavaScript 中比较字符串时，为什么一个字符串大于另一个? [英] Why is one string greater than the other when comparing strings in JavaScript?

问题描述

我从一本书中看到这段代码:

I see this code from a book:

var a = "one";
var b = "four";
a>b; // will return true

但它没有提到为什么一"比四"大.我试过 c = "a" 并且它比 a 和 b 小.我想知道 JavaScript 如何比较这些字符串.

but it doesn't mention why "one" is bigger than "four". I tried c = "a" and it is smaller than a and b. I want to know how JavaScript compares these strings.

推荐答案

因为，在许多编程语言中，比较字符串 按字典顺序.

Because, as in many programming languages, strings are compared lexicographically.

您可以将其视为 字母顺序 的更高级版本，区别在于字母顺序仅涵盖 a 到 z 的 26 个字符.

You can think of this as a fancier version of alphabetical ordering, the difference being that alphabetic ordering only covers the 26 characters a through z.

这个答案是对java 问题，但是逻辑完全一样.另一个不错的:字符串比较逻辑".

This answer is in response to a java question, but the logic is exactly the same. Another good one: String Compare "Logic".

这篇关于在 JavaScript 中比较字符串时，为什么一个字符串大于另一个?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！