带变量的支撑扩展? [英] Brace expansion with variable?

问题描述

#!/bin/sh
for i in {1..5}
do
   echo "Welcome"
done

行得通，显示欢迎 5 次.

Would work, displays Welcome 5 times.

#!/bin/sh
howmany=`grep -c $1 /root/file`
for i in {1..$howmany}
do
   echo "Welcome"
done

没用！howmany 将等于 5，因为这是 grep -c 的输出将显示的内容.$1 是运行脚本时特定的参数 1.

Doesn't work! howmany would equal 5 as that is what the output of grep -c would display. $1 is parameter 1 which is specific when running the script.

有什么想法吗?

推荐答案

创建一个序列来控制你的循环

create a sequence to control your loop

for i in $(seq 1 $howmany); do
echo "Welcome";
done

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