如何将包含斜杠的变量传递给 sed [英] How to pass a variable containing slashes to sed

问题描述

如何将包含斜杠的变量作为模式传递给 sed?

How do you pass a variable containing slashes as a pattern to sed?

例如，如果我有以下变量:

For example, if I have the following variable:

var="/Users/Documents/name/file"

我想将它传递给 sed 如下:

I want to pass it to sed as so:

sed "s/$var/replace/g" "$file"

但是我遇到了错误.我怎样才能规避这个问题?

However I get errors. How can I circumvent the issue?

推荐答案

使用备用正则表达式分隔符作为 sed 允许您使用任何分隔符(包括控制字符):

Use an alternate regex delimiter as sed allows you to use any delimiter (including control characters):

sed "s~$var~replace~g" $file

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如上所述，我们也可以使用控制字符作为分隔符:

---

As mentioned above we can use control character as delimiter as well like:

sed "s^[$var^[replace^[g" file

其中 ^[ 是通过同时按下 Ctrl-V-3 输入的.

Where ^[ is typed by pressing Ctrl-V-3 together.

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