如何找到两个日期之间的天数差异? [英] How to find the difference in days between two dates?

问题描述

A="2002-20-10"
B="2003-22-11"

A="2002-20-10"
B="2003-22-11"

如何求两个日期相差的天数?

How to find the difference in days between two dates?

推荐答案

如果你有 GNU date，它允许打印任意日期的表示 (-d选项).在这种情况下，将日期转换为自 EPOCH 以来的秒数，减去并除以 24*3600.

If you have GNU date, it allows to print the representation of an arbitrary date (-d option). In this case convert the dates to seconds since EPOCH, subtract and divide by 24*3600.

使用 GNU 日期的示例(来自 https://stackoverflow.com/a/9008871/215713):>

Example using GNU date (from https://stackoverflow.com/a/9008871/215713):

let DIFF=($(date +%s -d 20210131)-$(date +%s -d 20210101))/86400
echo $DIFF
30

这也适用于其他格式的日期，例如2021-01-31".

This also works with dates in other formats, for example "2021-01-31".

其他答案建议了不需要 GNU 日期的方法.

Other answers suggest ways to do it that don't require GNU date.

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