如何构建 Cloud Functions for Firebase 以从多个文件部署多个函数? [英] How do I structure Cloud Functions for Firebase to deploy multiple functions from multiple files?

问题描述

我想为 Firebase 创建多个 Cloud Functions 并从一个项目同时部署它们.我还想将每个函数分成一个单独的文件.目前，如果我将它们都放在 index.js 中，我可以创建多个函数，例如:

I would like to create multiple Cloud Functions for Firebase and deploy them all at the same time from one project. I would also like to separate each function into a separate file. Currently I can create multiple functions if I put them both in index.js such as:

exports.foo = functions.database.ref('/foo').onWrite(event => {
    ...
});

exports.bar = functions.database.ref('/bar').onWrite(event => {
    ...
});

但是我想将 foo 和 bar 放在单独的文件中.我试过这个:

However I would like to put foo and bar in separate files. I tried this:

/functions
|--index.js (blank)
|--foo.js
|--bar.js
|--package.json

foo.js 在哪里

exports.foo = functions.database.ref('/foo').onWrite(event => {
    ...
});

和 bar.js 是

exports.bar = functions.database.ref('/bar').onWrite(event => {
    ...
});

有没有办法在不将所有函数都放在 index.js 中的情况下实现这一点?

Is there a way to accomplish this without putting all functions in index.js?

推荐答案

啊，Firebase 加载节点模块的 Cloud Functions 函数正常，所以这有效

Ah, Cloud Functions for Firebase load node modules normally, so this works

结构:

/functions
|--index.js
|--foo.js
|--bar.js
|--package.json

index.js:

const functions = require('firebase-functions');
const fooModule = require('./foo');
const barModule = require('./bar');

exports.foo = functions.database.ref('/foo').onWrite(fooModule.handler);
exports.bar = functions.database.ref('/bar').onWrite(barModule.handler);

foo.js:

exports.handler = (event) => {
    ...
};

bar.js:

exports.handler = (event) => {
    ...
};

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