使用 curl 在 PHP 中获取 HTTP 代码 [英] Getting HTTP code in PHP using curl
问题描述
我正在使用 CURL 来获取站点的状态,如果它启动/关闭或重定向到另一个站点.我想尽可能简化它,但效果不佳.
I'm using CURL to get the status of a site, if it's up/down or redirecting to another site. I want to get it as streamlined as possible, but it's not working well.
<?php
$ch = curl_init($url);
curl_setopt($ch,CURLOPT_RETURNTRANSFER,1);
curl_setopt($ch,CURLOPT_TIMEOUT,10);
$output = curl_exec($ch);
$httpcode = curl_getinfo($ch, CURLINFO_HTTP_CODE);
curl_close($ch);
return $httpcode;
?>
我将它封装在一个函数中.它工作正常,但性能不是最好的,因为它下载整个页面,如果我删除 $output = curl_exec($ch);
它总是返回 0
.
I have this wrapped in a function. It works fine but performance is not the best because it downloads the whole page, thing in if I remove $output = curl_exec($ch);
it returns 0
all the time.
有谁知道如何使性能更好?
Does anyone know how to make the performance better?
推荐答案
首先确定 URL 是否实际有效(字符串,非空,语法良好),这样可以快速检查服务器端.例如,先执行此操作可以节省大量时间:
First make sure if the URL is actually valid (a string, not empty, good syntax), this is quick to check server side. For example, doing this first could save a lot of time:
if(!$url || !is_string($url) || ! preg_match('/^http(s)?://[a-z0-9-]+(.[a-z0-9-]+)*(:[0-9]+)?(/.*)?$/i', $url)){
return false;
}
确保您只获取标题,而不是正文内容:
Make sure you only fetch the headers, not the body content:
@curl_setopt($ch, CURLOPT_HEADER , true); // we want headers
@curl_setopt($ch, CURLOPT_NOBODY , true); // we don't need body
有关获取 URL 状态 http 代码的更多详细信息,我参考了我发表的另一篇文章(它也有助于以下重定向):
For more details on getting the URL status http code I refer to another post I made (it also helps with following redirects):
整体:
$url = 'http://www.example.com';
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_HEADER, true); // we want headers
curl_setopt($ch, CURLOPT_NOBODY, true); // we don't need body
curl_setopt($ch, CURLOPT_RETURNTRANSFER,1);
curl_setopt($ch, CURLOPT_TIMEOUT,10);
$output = curl_exec($ch);
$httpcode = curl_getinfo($ch, CURLINFO_HTTP_CODE);
curl_close($ch);
echo 'HTTP code: ' . $httpcode;
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