执行元组算术的优雅方式 [英] Elegant way to perform tuple arithmetic
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问题描述
在 Python 2.7 中执行元组算术的最优雅和简洁的方法是什么(无需创建我自己的带有运算符重载的类)?
假设我有两个元组:
a = (10, 10)b = (4, 4)
我想要的结果是
c = a - b = (6, 6)
我目前使用:
c = (a[0] - b[0], a[1] - b[1])
我也试过:
c = tuple([(i - j) for i in a for j in b])
但结果是(6, 6, 6, 6)
.我相信以上内容作为嵌套的 for 循环工作,结果中产生 4 次迭代和 4 个值.
解决方案
如果你正在寻找快速,你可以使用 numpy:
<预><代码>>>>导入 numpy>>>numpy.subtract((10, 10), (4, 4))数组([6, 6])如果你想把它保存在一个元组中:
<预><代码>>>>元组(numpy.subtract((10, 10), (4, 4)))(6, 6)What is the most elegant and concise way (without creating my own class with operator overloading) to perform tuple arithmetic in Python 2.7?
Lets say I have two tuples:
a = (10, 10)
b = (4, 4)
My intended result is
c = a - b = (6, 6)
I currently use:
c = (a[0] - b[0], a[1] - b[1])
I also tried:
c = tuple([(i - j) for i in a for j in b])
but the result was (6, 6, 6, 6)
. I believe the above works as a nested for loops resulting in 4 iterations and 4 values in the result.
解决方案
If you're looking for fast, you can use numpy:
>>> import numpy
>>> numpy.subtract((10, 10), (4, 4))
array([6, 6])
and if you want to keep it in a tuple:
>>> tuple(numpy.subtract((10, 10), (4, 4)))
(6, 6)
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