四舍五入到 n 个有效数字 [英] Rounding to n significant digits
本文介绍了四舍五入到 n 个有效数字的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试在 MATLAB 中编写代码,将数字四舍五入为某些(如我所问)有效数字.
I'm trying to write code in MATLAB that will round number to certain (as I ask) significant digits.
我不知道该怎么做.有什么建议吗?
I'm not sure how to do it. Any suggestions?
推荐答案
四舍五入到 d
有效数字:
>> d = 3; %// number of digits
>> x = 5.237234; %// example number
>> D = 10^(d-ceil(log10(x)));
>> y = round(x*D)/D
y =
5.2400
四舍五入到d
十进制数字:
>> d = 3; %// number of digits
>> x = 5.237234; %// example number
>> D = 10^d;
>> y = round(x*D)/D
y =
5.2370
编辑
实际上更简单:round
函数支持以下选项:
Actually it's easier: the round
function supports these options:
>> d = 3;
>> x = 5.237234;
>> y = round(x, d, 'significant')
y =
5.2400
>> d = 3;
>> x = 5.237234;
>> y = round(x, d) %// or y = round(x, d, 'decimals')
y =
5.2370
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