使用 JAX-RS 上传文件 [英] FileUpload with JAX-RS
问题描述
我尝试将文件从 JavaScript 客户端上传到 JAX-RS Java 服务器.
I try to do file upload from a JavaScript client to a JAX-RS Java server.
我在我的服务器上使用以下 REST 上传功能:
I use the following REST upload function on my server:
@POST
@Produces('application/json')
UploadDto upload(
@Context HttpServletRequest request,
@QueryParam("cookie") String cookie) {
def contentType
byte [] fileBytes
log.debug "upload - cookie: "+cookie
try{
if (request instanceof MultipartHttpServletRequest) {
log.debug "request instanceof MultipartHttpServletRequest"
MultipartHttpServletRequest myrequest = request
CommonsMultipartFile file = (CommonsMultipartFile) myrequest.getFile('file')
fileBytes = file.bytes
contentType = file.contentType
log.debug ">>>>> upload size of the file in byte: "+ file.size
}
else if (request instanceof SecurityContextHolderAwareRequestWrapper) {
log.debug "request instanceof SecurityContextHolderAwareRequestWrapper"
SecurityContextHolderAwareRequestWrapper myrequest = request
//get uploaded file's inputStream
InputStream inputStream = myrequest.inputStream
fileBytes = IOUtils.toByteArray(inputStream);
contentType = myrequest.getHeader("Content-Type")
log.debug ">>>>> upload size of the file in byte: "+ fileBytes.size()
}
else {
log.error "request is not a MultipartHttpServletRequest or SecurityContextHolderAwareRequestWrapper"
println "request: "+request.class
}
}
catch (IOException e) {
log.error("upload() failed to save file error: ", e)
}
}
在客户端,我按如下方式发送文件:
On the client side I send the file as follows:
var str2ab_blobreader = function(str, callback) {
var blob;
BlobBuilder = window.MozBlobBuilder || window.WebKitBlobBuilder
|| window.BlobBuilder;
if (typeof (BlobBuilder) !== 'undefined') {
var bb = new BlobBuilder();
bb.append(str);
blob = bb.getBlob();
} else {
blob = new Blob([ str ]);
}
var f = new FileReader();
f.onload = function(e) {
callback(e.target.result)
}
f.readAsArrayBuffer(blob);
}
var fileName = "fileName.jpg";
var contentType = "image/jpeg";
if (file.type.toString().toLowerCase().indexOf("png") > -1) {
fileName = "fileName.png";
contentType = "image/png";
}
var xhrNativeObject = new XMLHttpRequest();
var urlParams = ?test=123;
xhrNativeObject.open("post", url + urlParams, true);
xhrNativeObject.setRequestHeader("Content-Type", contentType);
xhrNativeObject.onload = function(event) {
var targetResponse = event.currentTarget;
if ((targetResponse.readyState == 4)
&& (targetResponse.status == 200)) {
var obj = JSON.parse(targetResponse.responseText);
console.log(obj.uploadImageId);
} else {
console.log("fail");
}
}
var buffer = str2ab_blobreader(file, function(buf) {
xhrNativeObject.send(buf);
});
当我在 Grails 控制器中使用代码时,它运行良好,但当我在 REST 资源中使用它时,我总是得到:请求不是 MultipartHttpServletRequest 或 SecurityContextHolderAwareRequestWrapper
When I use the code in my Grails Controller it worked well but when I use it in a REST Resource I always get: request is not a MultipartHttpServletRequest or SecurityContextHolderAwareRequestWrapper
日志输出为
request: com.sun.proxy.$Proxy58
从 JavaScript 发送文件 blob 我使用 XMLHttpRequest
,其中包含正文中的 blob 和一些查询参数.
The send a file blob from JavaScript I use XMLHttpRequest
which contains the blob in the body and some query parameters.
如何让 JAX-RS 文件上传工作?我如何通过 POST 请求接收一些额外的查询参数?
推荐答案
在服务器端,你可以使用这样的东西
On Server Side you can use something like this
@POST
@Path("/fileupload") //Your Path or URL to call this service
@Consumes(MediaType.MULTIPART_FORM_DATA)
public Response uploadFile(
@DefaultValue("true") @FormDataParam("enabled") boolean enabled,
@FormDataParam("file") InputStream uploadedInputStream,
@FormDataParam("file") FormDataContentDisposition fileDetail) {
//Your local disk path where you want to store the file
String uploadedFileLocation = "D://uploadedFiles/" + fileDetail.getFileName();
System.out.println(uploadedFileLocation);
// save it
File objFile=new File(uploadedFileLocation);
if(objFile.exists())
{
objFile.delete();
}
saveToFile(uploadedInputStream, uploadedFileLocation);
String output = "File uploaded via Jersey based RESTFul Webservice to: " + uploadedFileLocation;
return Response.status(200).entity(output).build();
}
private void saveToFile(InputStream uploadedInputStream,
String uploadedFileLocation) {
try {
OutputStream out = null;
int read = 0;
byte[] bytes = new byte[1024];
out = new FileOutputStream(new File(uploadedFileLocation));
while ((read = uploadedInputStream.read(bytes)) != -1) {
out.write(bytes, 0, read);
}
out.flush();
out.close();
} catch (IOException e) {
e.printStackTrace();
}
}
同样可以使用 java 中的客户端代码进行检查
Again this can be checked with the client code in java with
public class TryFile {
public static void main(String[] ar)
throws HttpException, IOException, URISyntaxException {
TryFile t = new TryFile();
t.method();
}
public void method() throws HttpException, IOException, URISyntaxException {
String url = "http://localhost:8080/...../fileupload"; //Your service URL
String fileName = ""; //file name to be uploaded
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(url);
FileBody fileContent = new FiSystem.out.println("hello");
StringBody comment = new StringBody("Filename: " + fileName);
MultipartEntity reqEntity = new MultipartEntity();
reqEntity.addPart("file", fileContent);
httppost.setEntity(reqEntity);
HttpResponse response = httpclient.execute(httppost);
HttpEntity resEntity = response.getEntity();
}
}
使用 HTML,您可以简单地检查此代码
With HTML, you can simply check with this code
<html>
<body>
<h1>Upload File with RESTFul WebService</h1>
<form action="<Your service URL (htp://localhost:8080/.../fileupload)" method="post" enctype="multipart/form-data">
<p>
Choose a file : <input type="file" name="file" />
</p>
<input type="submit" value="Upload" />
</form>
要获取QueryParam,请检查@QueryParam 或使用@HeaderParam 获取标题参数
To get QueryParam, Check @QueryParam or for header param use @HeaderParam
试试这个,希望这能帮助你解决问题.
Try this, hope this helps you with your problem.
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