如何在 Python 中迭代两个或多个列表的项的元组? [英] How do I iterate over the tuples of the items of two or more lists in Python?

问题描述

具体来说，我有两个字符串列表，我想将它们组合成一个字符串，其中每一行是列表中的下两个字符串，用空格分隔:

Specifically, I have two lists of strings that I'd like to combine into a string where each line is the next two strings from the lists, separated by spaces:

a = ['foo1', 'foo2', 'foo3']
b = ['bar1', 'bar2', 'bar3']

我想要一个会返回的函数 combine_to_lines() :

I want a function combine_to_lines() that would return:

"""foo1 bar1
foo2 bar2
foo3 bar3"""

我承认我已经解决了这个问题，所以我要发布答案.但也许其他人有更好的或看到我的缺陷.

I admit I've already solved this problem, so I'm going to post the answer. But perhaps someone else has a better one or sees a flaw in mine.

更新:我过度简化了上面的示例.在我的实际问题中，这些行以更复杂的方式格式化，需要解压缩从 zip() 返回的元组.但感谢 mhawke 为这个例子提出最简单的解决方案.

Update: I over-simplified my example above. In my real-world problem the lines were formatted in a more complicated manner that required the tuples returned from zip() to be unpacked. But kudos to mhawke for coming up to the simplest solution to this example.

推荐答案

zip 返回的元组没有必要解包和重新打包:

It's not necessary to unpack and repack the tuples returned by zip:

'
'.join(' '.join(x) for x in zip(a, b))

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