Android:从内容 URI 中获取文件 URI? [英] Android: Getting a file URI from a content URI?
问题描述
在我的应用程序中，用户将选择应用程序处理的音频文件.问题是，为了让应用程序执行我希望它对音频文件执行的操作，我需要 URI 为文件格式.当我使用Android的原生音乐播放器在app中浏览音频文件时，URI为内容URI，如下所示:
In my app the user is to select an audio file which the app then handles. The problem is that in order for the app to do what I want it to do with the audio files, I need the URI to be in file format. When I use Android's native music player to browse for the audio file in the app, the URI is a content URI, which looks like this:
content://media/external/audio/media/710
但是，使用流行的文件管理器应用程序 Astro，我得到以下信息:
However, using the popular file manager application Astro, I get the following:
file:///sdcard/media/audio/ringtones/GetupGetOut.mp3
后者对我来说更容易使用，但当然我希望应用程序具有用户选择的音频文件的功能，而不管他们使用什么程序浏览他们的收藏.所以我的问题是，有没有办法将 content:// 样式 URI 转换为 file:// URI?否则，您会为我推荐什么来解决这个问题?下面是调用选择器的代码，供参考:
The latter is much more accessible for me to work with, but of course I want the app to have functionality with the audio file the user chooses regardless of the program they use to browse their collection. So my question is, is there a way to convert the content:// style URI into a file:// URI? Otherwise, what would you recommend for me to solve this problem? Here is the code which calls up the chooser, for reference:
Intent ringIntent = new Intent();
ringIntent.setType("audio/mp3");
ringIntent.setAction(Intent.ACTION_GET_CONTENT);
ringIntent.addCategory(Intent.CATEGORY_OPENABLE);
startActivityForResult(Intent.createChooser(ringIntent, "Select Ringtone"), SELECT_RINGTONE);
我对内容 URI 执行以下操作:
I do the following with the content URI:
m_ringerPath = m_ringtoneUri.getPath();
File file = new File(m_ringerPath);
然后对所述文件执行一些 FileInputStream 操作.
Then do some FileInputStream stuff with said file.
推荐答案
只需使用 getContentResolver().openInputStream(uri) 从 URI 中获取 InputStream.
Just use getContentResolver().openInputStream(uri) to get an InputStream from a URI.
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