Symfony 2 中默认 Monolog 的自定义 Monolog 处理程序 [英] Custom monolog handler for default monolog in Symfony 2

问题描述

我想向 Symfony 2 中的默认 Monolog 添加自定义处理程序.

I want to add a custom handler to a default monolog in Symfony 2.

在我的 config.yaml 文件中，我有:

In my config.yaml file, I have:

monolog:
    handlers:
        main:
            type:  stream
            path:  %kernel.logs_dir%/%kernel.environment%.log
            level: debug
        myHandler:
            type:  AcmeMyBundleMonologMyCustomHandler
            level: error

我的类如下所示:

// AcmeMyBundleMonologMyCustomHandler
use MonologLogger;
use MonologHandlerSocketHandler;
use MonologFormatterLineFormatter;

class MyCustomHandler extends AbstractProcessingHandler
{
    ...
}

但即使在我填写我的课程之前，我也收到了一个错误:

But even before I fill my class in I get an error:

为处理程序myHandler"提供的无效处理程序类型acmemybundlemonologmycustomhandler"

invalid handler type "acmemybundlemonologmycustomhandler" given for handler "myHandler"

如何在不创建新的 Monolog 服务的情况下向默认 Monolog 添加自定义处理程序?

How do I add a custom handler to the default monolog without creating a new monolog service?

推荐答案

试试这个:

monolog:
    handlers:
        main:
            type:  stream
            path:  %kernel.logs_dir%/%kernel.environment%.log
            level: debug
        custom:
            type: service
            id: my_custom_handler

services:
    my_custom_handler:
        class: AcmeMyBundleMonologMyCustomHandler

如果你想把它用作默认处理程序，那么你应该改变我上面写的一点独白部分.

If you want to use it as default handler then you should change a bit monolog section I wrote above.

monolog:
    handlers:
        main:
            type:  stream
            path:  %kernel.logs_dir%/%kernel.environment%.log
            level: debug
            handler: custom
        custom:
            type: service
            id: my_custom_handler

希望能帮到你.

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