使用 Perl 打开文本文件并将其读入数组的最简单方法 [英] Easiest way to open a text file and read it into an array with Perl

问题描述

为我拥有的每个脚本添加一个标准的 Perl 文件打开函数有点烦人:

Adding a standard Perl file open function to each script I have is a bit annoying:

sub openfile{
    (my $filename) = @_;
    open FILE,"$filename" or die $!;
    my @lines = <FILE>;
    return @lines;
}

我可以创建一个 Perl 模块来执行此操作，但这太简单了，我相信应该已经有一个了.

and I can create a Perl module to do this, but this is so simple I'm sure there should be one out there already.

我正在尝试找到一种将文本文件读入数组的方法，但我似乎找不到可以完成这项简单任务的 Perl 模块...随附标准 5.10 安装.

I'm trying to find a way to read a text file into an array, and I cant seem to find a Perl module out there that can do this simple task... maybe I'm looking too hard and it already came with the standard 5.10 install.

最好我相信它看起来像这样:

Optimally I believe it would look something like this:

my @lines = Module::File::Read("c:somefolderstructurefile.txt");

推荐答案

你有几个选择，经典的do方法:

You have several options, the classic do method:

my @array = do {
    open my $fh, "<", $filename
        or die "could not open $filename: $!";
    <$fh>;
};

IO::All 方法:

use IO::All;

my @array = io($filename)->slurp;

File::Slurp 方法:

use File::Slurp;

my @array = read_file($filename);

也许还有更多，毕竟TIMTOWTDI.

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