是否可以捕获 JavaScript 异步回调中抛出的异常? [英] Is it possible to catch exceptions thrown in a JavaScript async callback?
问题描述
有没有办法在 JavaScript 回调中捕获异常?甚至有可能吗?
Is there a way to catch exceptions in JavaScript callbacks? Is it even possible?
Uncaught Error: Invalid value for property <address>
这里是jsfiddle:http://jsfiddle.net/kjy112/yQhhy/>
Here is the jsfiddle: http://jsfiddle.net/kjy112/yQhhy/
try {
// this will cause an exception in google.maps.Geocoder().geocode()
// since it expects a string.
var zipcode = 30045;
var map = new google.maps.Map(document.getElementById('map_canvas'), {
zoom: 5,
center: new google.maps.LatLng(35.137879, -82.836914),
mapTypeId: google.maps.MapTypeId.ROADMAP
});
// exception in callback:
var geo = new google.maps.Geocoder().geocode({ 'address': zipcode },
function(geoResult, geoStatus) {
if (geoStatus != google.maps.GeocoderStatus.OK) console.log(geoStatus);
}
);
} catch (e) {
if(e instanceof TypeError)
alert('TypeError');
else
alert(e);
}
推荐答案
在你的例子中它不会捕获任何东西的原因是因为一旦 geocode()
回调被调用,try/catch
块结束.因此 geocode()
回调在 try
块的范围之外执行,因此无法被它捕获.
The reason it won't catch anything in your example is because once the geocode()
callback is called, the try/catch
block is over. Therefore the geocode()
callback is executed outside the scope of the try
block and thus not catchable by it.
据我所知,无法捕获 JavaScript 回调中抛出的异常(至少,不是以任何直接的方式).
As far as I know, it is not possible to catch exceptions thrown in JavaScript callbacks (at least, not in any straightforward manner).
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