在 Python 中将 N 秒添加到 datetime.time 的标准方法是什么? [英] What is the standard way to add N seconds to datetime.time in Python?
问题描述
给定 Python 中的 datetime.time
值,是否有一种标准方法可以向其添加整数秒数,以便 11:34:59
+ 3= 11:35:02
,例如?
这些显而易见的想法行不通:
<预><代码>>>>日期时间.时间(11, 34, 59) + 3类型错误:不支持 + 的操作数类型:'datetime.time' 和 'int'>>>datetime.time(11, 34, 59) + datetime.timedelta(0, 3)类型错误:+ 不支持的操作数类型:datetime.time"和datetime.timedelta">>>datetime.time(11, 34, 59) + datetime.time(0, 0, 3)类型错误:不支持 + 的操作数类型:'datetime.time' 和 'datetime.time'最后我写了这样的函数:
def add_secs_to_time(timeval, secs_to_add):秒 = timeval.hour * 3600 + timeval.minute * 60 + timeval.second秒 += secs_to_addreturn datetime.time(secs//3600, (secs % 3600)//60, secs % 60)
我不禁想到我错过了一种更简单的方法来做到这一点.
相关
您可以将完整的 datetime
变量与 timedelta
一起使用,并通过提供一个虚拟日期然后使用 time
获取时间值.
例如:
导入日期时间a = datetime.datetime(100,1,1,11,34,59)b = a + datetime.timedelta(0,3) # 天,秒,然后是其他字段.打印(a.time())打印(b.time())
产生两个值,相隔三秒:
11:34:5911:35:02
你也可以选择更易读的
b = a + datetime.timedelta(seconds=3)
如果你愿意的话.
<小时>如果您想要一个可以执行此操作的函数,您可以考虑使用下面的 addSecs
:
导入日期时间def addSecs(tm, secs):fulldate = datetime.datetime(100, 1, 1, tm.hour, tm.minute, tm.second)fulldate = fulldate + datetime.timedelta(seconds=secs)返回 fulldate.time()a = datetime.datetime.now().time()b = addSecs(a, 300)打印(一)打印(b)
输出:
09:11:55.77569509:16:55
Given a datetime.time
value in Python, is there a standard way to add an integer number of seconds to it, so that 11:34:59
+ 3 = 11:35:02
, for example?
These obvious ideas don't work:
>>> datetime.time(11, 34, 59) + 3
TypeError: unsupported operand type(s) for +: 'datetime.time' and 'int'
>>> datetime.time(11, 34, 59) + datetime.timedelta(0, 3)
TypeError: unsupported operand type(s) for +: 'datetime.time' and 'datetime.timedelta'
>>> datetime.time(11, 34, 59) + datetime.time(0, 0, 3)
TypeError: unsupported operand type(s) for +: 'datetime.time' and 'datetime.time'
In the end I have written functions like this:
def add_secs_to_time(timeval, secs_to_add):
secs = timeval.hour * 3600 + timeval.minute * 60 + timeval.second
secs += secs_to_add
return datetime.time(secs // 3600, (secs % 3600) // 60, secs % 60)
I can't help thinking that I'm missing an easier way to do this though.
Related
You can use full datetime
variables with timedelta
, and by providing a dummy date then using time
to just get the time value.
For example:
import datetime
a = datetime.datetime(100,1,1,11,34,59)
b = a + datetime.timedelta(0,3) # days, seconds, then other fields.
print(a.time())
print(b.time())
results in the two values, three seconds apart:
11:34:59
11:35:02
You could also opt for the more readable
b = a + datetime.timedelta(seconds=3)
if you're so inclined.
If you're after a function that can do this, you can look into using addSecs
below:
import datetime
def addSecs(tm, secs):
fulldate = datetime.datetime(100, 1, 1, tm.hour, tm.minute, tm.second)
fulldate = fulldate + datetime.timedelta(seconds=secs)
return fulldate.time()
a = datetime.datetime.now().time()
b = addSecs(a, 300)
print(a)
print(b)
This outputs:
09:11:55.775695
09:16:55
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