重新创建套接字时绑定错误 [英] Bind error while recreating socket

问题描述

A 有以下侦听器套接字:

A have the following listener socket:

int sd = socket(PF_INET, SOCK_STREAM, 0);

struct sockaddr_in addr;
bzero(&addr, sizeof(addr));
addr.sin_family = AF_INET;
addr.sin_port = htons(http_port);
addr.sin_addr.s_addr = INADDR_ANY;

if(bind(sd,(sockaddr*)&addr,sizeof(addr))!=0)
{
    ...
}

if (listen(sd, 16)!=0)
{
    ...
}

int sent = 0;
for(;;) {
    int client = accept(sd, (sockaddr*)&addr, (socklen_t*)&size);
    if (client > 0)
    {
        ...
        close(client);
    }
}

如果使用

close(sd);

然后尝试使用相同的代码重新创建套接字，发生绑定错误，并且仅在 30-60 秒后成功创建新套接字.

and then trying to recreate socket with the same code, a bind error happens, and only after 30-60 second a new socket is created successfully.

有没有办法以某种很酷的方式创建或关闭来避免绑定错误?

It there a way to create or close in some cool way to avoid bind error?

推荐答案

在内核的某个地方，仍然有一些关于您以前的套接字的信息.告诉内核你无论如何都愿意重用这个端口:

Somewhere in the kernel, there's still some information about your previous socket hanging around. Tell the kernel that you are willing to re-use the port anyway:

int yes=1;
//char yes='1'; // use this under Solaris

if (setsockopt(sockfd, SOL_SOCKET, SO_REUSEADDR, &yes, sizeof(yes)) == -1) {
    perror("setsockopt");
    exit(1);
}

参见 beej 网络编程指南中的 bind() 部分 更详细的解释.

See the bind() section in beej's Guide to Network Programming for a more detailed explanation.

这篇关于重新创建套接字时绑定错误的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！