在 Go 程序中捆绑静态资源的最佳方法是什么? [英] What's the best way to bundle static resources in a Go program?

问题描述

我正在使用 Go 开发一个小型网络应用程序，该应用程序旨在用作开发人员机器上的工具，以帮助调试他们的应用程序/网络服务.该程序的界面是一个网页，它不仅包括 HTML，还包括一些 JavaScript(用于功能)、图像和 CSS(用于样式).我打算开源这个应用程序，所以用户应该能够简单地运行一个 Makefile，所有的资源都会去他们需要去的地方.但是，我还希望能够简单地分发具有尽可能少的文件/依赖项的可执行文件.有没有什么好办法将 HTML/CSS/JS 与可执行文件捆绑在一起，让用户只需要下载一个文件就可以了?

I'm working on a small web application in Go that's meant to be used as a tool on a developer's machine to help debug their applications/web services. The interface to the program is a web page which includes not only the HTML, but some JavaScript (for functionality), images and CSS (for styling). I'm planning on open-sourcing this application, so users should simply be able to run a Makefile and all the resources will go where they need to go. However, I'd also like to be able to simply distribute an executable with as few files/dependencies as possible. Is there a good way to bundle the HTML/CSS/JS with the executable, so users only have to download and worry about one file?

现在，在我的应用中，提供静态文件看起来有点像这样:

Right now, in my app, serving a static file looks a little like this:

// called via http.ListenAndServe
func switchboard(w http.ResponseWriter, r *http.Request) {

    // snipped dynamic routing...

    // look for static resource
    uri := r.URL.RequestURI()
    if fp, err := os.Open("static" + uri); err == nil {
        defer fp.Close()
        staticHandler(w, r, fp)
        return
    }

    // snipped blackhole route
}

所以这很简单:如果请求的文件存在于我的静态目录中，则调用处理程序，它只是打开文件并尝试在服务之前设置一个好的 Content-Type.我的想法是没有理由这需要基于真实的文件系统:如果有已编译的资源，我可以简单地通过请求 URI 为它们编制索引，并为它们提供服务.

So it's pretty simple: if the requested file exists in my static directory, invoke the handler, which simply opens the file and tries to set a good Content-Type before serving. My thought was that there's no reason this needs to be based on the real filesystem: if there were compiled resources, I could simply index them by the request URI and serve them as such.

如果没有好的方法可以做到这一点，或者我试图这样做是在找错树，请告诉我.我只是认为最终用户会希望管理尽可能少的文件.

If there's not a good way to do this, or I'm barking up the wrong tree by trying to do this, let me know. I just figured the end-user would appreciate as few files as possible to manage.

^{如果有比go，请随时添加它们或让我知道.}

^{If there are more appropriate tags than go, please feel free to add them or let me know.}

推荐答案

go-bindata 包看起来可能正是您感兴趣的内容.

The go-bindata package looks like it might be what you're interested in.

https://github.com/go-bindata/go-bindata

它将允许您将任何静态文件转换为可以嵌入到代码中的函数调用，并在调用时返回文件内容的字节切片.

It will allow you to convert any static file into a function call that can be embedded in your code and will return a byte slice of the file content when called.

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