这些关于指针的陈述是否具有相同的效果? [英] Do these statements about pointers have the same effect?

问题描述

这样做...

char* myString = "hello";

...和这个效果一样吗?

... have the same effect as this?

char actualString[] = "hello";
char* myString = actualString;

推荐答案

没有

char  str1[] = "Hello world!"; //char-array on the stack; string can be changed
char* str2   = "Hello world!"; //char-array in the data-segment; it's READ-ONLY

第一个示例在堆栈上创建一个大小为 13*sizeof(char) 的数组，并将字符串 "Hello world!" 复制到其中.
第二个示例在堆栈上创建一个 char* 并将其指向可执行文件数据段中的一个位置，其中包含字符串 "Hello world!".第二个字符串是只读.

The first example creates an array of size 13*sizeof(char) on the stack and copies the string "Hello world!" into it.
The second example creates a char* on the stack and points it to a location in the data-segment of the executable, which contains the string "Hello world!". This second string is READ-ONLY.

str1[1] = 'u'; //Valid
str2[1] = 'u'; //Invalid - MAY crash program!

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