如何删除批处理文件中用户提供的输入的尾随和前导空格? [英] How to remove trailing and leading whitespace for user-provided input in a batch file?

问题描述

我知道如何在预定义变量时执行此操作.但是，当要求用户输入某种输入时，如何修剪前导和尾随空格?这是我目前所拥有的:

I know how to do this when the variable is pre-defined. However, when asking for the user to enter in some kind of input, how do I trim leading and trailing whitespace? This is what I have so far:

@echo off

set /p input=:
echo. The input is %input% before

::trim left whitespace
for /f "tokens=* delims= " %%a in ("%input%") do set input=%%a
::trim right whitespace (up to 100 spaces at the end)
for /l %%a in (1,1,100) do if "!input:~-1!"==" " set input=!input:~0,-1! 

echo. The input is %input% after

pause

推荐答案

您需要启用延迟扩展.试试这个:

You need to enable delayed expansion. Try this:

@echo off
setlocal enabledelayedexpansion
:blah
set /p input=:
echo."%input%"
for /f "tokens=* delims= " %%a in ("%input%") do set input=%%a
for /l %%a in (1,1,100) do if "!input:~-1!"==" " set input=!input:~0,-1!
echo."%input%"
pause
goto blah

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