获取上次创建的目录批处理命令 [英] Get last created directory batch command

问题描述

如何在目录中获取最新的子文件夹?
我在 MKLINK/D 命令中需要它.

How can i get newest subfolder in directory ?
I need it in MKLINK /D command.

谢谢

推荐答案

FOR /F "delims=" %%i IN ('dir /b /ad-h /t:c /od') DO SET a=%%i
echo Most recent subfolder: %a%

(%i for windows 10)

(%i for windows 10)

• /b 用于裸格式
• /ad-h 只有目录，而不是隐藏的目录
• t:c 表示使用创建日期进行排序(使用 t:w 为最后写入日期)
• /od 先排序最旧
• for/F 执行命令并设置a为目录名，最后一个是最新的.

• /b is for bare format
• /ad-h only directories, but not the hidden ones
• t:c means to use the creation date for sorting (use t:w for last write date)
• /od sort oldest first
• The for /F executes the command and sets a to the directory name, the last one is the newest one.

如果您直接在命令行(而不是在批处理文件中)执行此操作，请使用 % 而不是 %%.

If you execute this directly on the command line (not in a batch file), use % instead of %%.

这适用于当前目录 - 正如@iesou 指出的，如果您需要使用任何其他目录路径，则需要在 dir 之后添加目录路径.

This works with the current directory - as @iesou pointed out you'll need to add the directory path after dir if you need to use any other directory path.

具有指定目录路径的示例:

Example with specified directory path:

FOR /F "delims=" %%i IN ('dir "c:Program Files" /b /ad-h /t:c /od') DO SET a=%%i

<小时>

为了防止遍历所有子文件夹，您可以将排序顺序更改为最近的在前 (/o-d) 并在第一次调用后退出 for 循环:

---

To prevent going through all subfolders, you may change the sort order to have the most recent first (/o-d) and exit the for loop after the first call:

@echo off
FOR /F "delims=" %%i IN ('dir /b /ad-h /t:c /o-d') DO (
    SET a=%%i
    GOTO :found
)
echo No subfolder found
goto :eof
:found
echo Most recent subfolder: %a%

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