如何 typedef 模板类? [英] How to typedef a template class?

问题描述

我应该如何typedef模板类?类似的东西:

How should I typedef a template class ? Something like:

typedef std::vector myVector;  // <--- compiler error

我知道两种方法:

(1) #define myVector std::vector // not so good
(2) template<typename T>
    struct myVector { typedef std::vector<T> type; }; // verbose

我们在 C++0x 中有什么更好的吗?

Do we have anything better in C++0x ?

推荐答案

是的.它被称为别名模板"，它是 C+ 中的一项新功能+11.

Yes. It is called an "alias template," and it's a new feature in C++11.

template<typename T>
using MyVector = std::vector<T, MyCustomAllocator<T>>;

使用将完全符合您的预期:

Usage would then be exactly as you expect:

MyVector<int> x; // same as: std::vector<int, MyCustomAllocator<int>>

GCC 从 4.7 开始支持，Clang 从 3.0 开始支持，MSVC 在 2013 SP4 开始支持.

GCC has supported it since 4.7, Clang has it since 3.0, and MSVC has it in 2013 SP4.

这篇关于如何 typedef 模板类?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！