如何使用 url 访问 Python 中的 s3 文件? [英] How can I access s3 files in Python using urls?

问题描述

我想编写一个 Python 脚本，该脚本将使用 s3 的 url 读取和写入文件，例如:'s3:/mybucket/file'.它需要在本地和云端运行，无需任何代码更改.有没有办法做到这一点?

I want to write a Python script that will read and write files from s3 using their url's, eg:'s3:/mybucket/file'. It would need to run locally and in the cloud without any code changes. Is there a way to do this?

这里有一些很好的建议，但我真正想要的是允许我这样做的东西:

There are some good suggestions here but what I really want is something that allows me to do this:

 myfile = open("s3://mybucket/file", "r")

然后像使用任何其他文件对象一样使用该文件对象.那真的很酷.如果它不存在，我可能只是为自己写这样的东西.我可以在 simples3 或 boto 上构建抽象层.

and then use that file object like any other file object. That would be really cool. I might just write something like this for myself if it doesn't exist. I could build that abstraction layer on simples3 or boto.

推荐答案

对于开场，应该是这么简单:

For opening, it should be as simple as:

import urllib
opener = urllib.URLopener()
myurl = "https://s3.amazonaws.com/skyl/fake.xyz"
myfile = opener.open(myurl)

如果文件是公开的，这将适用于 s3.

This will work with s3 if the file is public.

要使用 boto 编写文件，它有点像这样:

To write a file using boto, it goes a little something like this:

from boto.s3.connection import S3Connection
conn = S3Connection(AWS_KEY, AWS_SECRET)
bucket = conn.get_bucket(BUCKET)
destination = bucket.new_key()
destination.name = filename
destination.set_contents_from_file(myfile)
destination.make_public()

让我知道这是否适合你:)

lemme know if this works for you :)

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