当返回类型为 ActionResult 时，如何对操作进行单元测试? [英] How to unit-test an action, when return type is ActionResult?

问题描述

我已经为以下操作编写了单元测试.

I have written unit test for following action.

[HttpPost]
public ActionResult/*ViewResult*/ Create(MyViewModel vm)
{
    if (ModelState.IsValid)
    {
        //Do something...
        return RedirectToAction("Index");
    }

    return View(vm);
}

测试方法可以访问Model属性，只有返回类型为ViewResult.在上面的代码中，我使用了 RedirectToAction 所以这个动作的返回类型不能是 ViewResult.

Test method can access Model properties, only when return type is ViewResult. In above code, I have used RedirectToAction so return type of this action can not be ViewResult.

在这种情况下，您如何对操作进行单元测试?

In such scenario how do you unit-test an action?

推荐答案

这是我的小例子:

public ActionResult Index(int id)
{
  if (1 != id)
  {
    return RedirectToAction("asd");
  }
  return View();
}

还有测试:

[TestMethod]
public void TestMethod1()
{
  HomeController homeController = new HomeController();
  ActionResult result = homeController.Index(10);
  Assert.IsInstanceOfType(result,typeof(RedirectToRouteResult));
  RedirectToRouteResult routeResult = result as RedirectToRouteResult;
  Assert.AreEqual(routeResult.RouteValues["action"], "asd");
}

[TestMethod]
public void TestMethod2()
{
  HomeController homeController = new HomeController();
  ActionResult result = homeController.Index(1);
  Assert.IsInstanceOfType(result, typeof(ViewResult));
}

确认结果类型为 ViewResut 后，您可以将其转换为:

Once you verified that the result type is ViewResut you can cast to it:

ViewResult vResult = result as ViewResult;
if(vResult != null)
{
  Assert.IsInstanceOfType(vResult.Model, typeof(YourModelType));
  YourModelType model = vResult.Model as YourModelType;
  if(model != null)
  {
    //...
  }
}

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