Web Api Request.CreateResponse HttpResponseMessage 没有智能感知 VS2012 [英] Web Api Request.CreateResponse HttpResponseMessage no intellisense VS2012

问题描述

出于某种原因，Request.CreateResponse 在 VS2012 中现在是红色"，当我将鼠标悬停在使用上时，IDE 说

For some reason, Request.CreateResponse is now "red" in VS2012 and when I hover over the usage the IDE says

无法解析符号CreateResponse"

Cannot resolve symbol 'CreateResponse'

这是 ApiController 类:

Here is the ApiController Class:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Net;
using System.Net.Http;
using System.Web.Http;
using System.Web.Http.Filters;
using GOCApi.Attributes;
using GOCApi.Models;
using GOCApi.Models.Abstract;
using AttributeRouting;
using AttributeRouting.Web.Http;

namespace GOCApi.Controllers
{
    [RoutePrefix("Courses")]
    public class CoursesController : ApiController
    {
        private ICoursesRepository _coursesRepository { get; set; }

        public CoursesController(ICoursesRepository coursesRepository)
        {
            _coursesRepository = coursesRepository;
        }

        [GET("{id}")]
        public HttpResponseMessage Get(int id)
        {
            var course = _coursesRepository.GetSingle(id);
            if (course == null)
            return Request.CreateResponse(HttpStatusCode.NotFound, "Invalid ID");
            return Request.CreateResponse(HttpStatusCode.OK, course);
        }
    }
}

当然，代码确实可以编译并运行，看到屏幕上所有的红色"真的很烦人.此外，当我输入 Request.CreateResponse 时，智能感知现在不起作用.这也曾经有效，但我开始为我的 API 开发其他部分，然后又回到构建控制器，所以我不知道发生了什么.

Granted, the code does compile and works, it's just really annoying seeing all the "red" on my screen. Also, the intellisense doesn't work now when I type Request.CreateResponse. This also used to work, but I started developing other parts to my API and just came back to building controllers so I do not know what happened.

有什么想法吗?

推荐答案

您需要添加对 System.Net.Http.Formatting.dll 的引用.CreateResponse 扩展方法在那里定义.

You need to add a reference to System.Net.Http.Formatting.dll. The CreateResponse extension method is defined there.

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