将特定 servlet 映射为 Tomcat 中的默认 servlet [英] Mapping a specific servlet to be the default servlet in Tomcat

查看：24 发布时间：2021/12/16 21:10:29 java tomcat servlets url-pattern

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问题描述

我正在尝试实现一个获取原始请求的 servlet，并决定是处理它们，还是将它们转发到另一个后端服务器.它类似于负载平衡器，其中接收到的请求被转发到(在我的情况下为 2)目的地之一.目的地之一是远程的(在另一台主机上).此外，请求可能会到达根目录(http://mycompany.com/).

I am trying to implement a servlet that gets raw requests, and decide either to process them, or forward them to another backend server. It is similar to a load-balancer, where a received request is forwarded to one of the (in my case 2) destinations. One of the destination is remote (on another host). Furthermore, the requests could come to the root (http://mycompany.com/).

因为我想获得原始请求，所以我实现了自己的 servlet(子类化 HttpServlet)，而且效果很好.我的 servlet 看起来像:

Since I want to get raw requests, I implemented my own servlet (subclassing HttpServlet), and that works great. My servlet looks like:

public class MyProxyServlet extends HttpServlet {
    @Override
    protected void doPost(HttpServletRequest req, HttpServletResponse resp)
        throws ServletException, IOException {
        processOrForward(req, resp);
    }
    // also doGet(), doHead(), ...
}

由于我要处理的服务可能会向根发送请求，因此我想将我的 servlet 映射为默认 servlet，从而接收任何没有显式 servlet 映射的请求.假设我的 servlet 的名称是myservlet"，并且与另一个 servletfoo"一起运行，我希望所有请求都采用 http://mycompany.com/foo/... 将传送到 foo，其他所有内容(例如/、/bar/...、/myservlet/...)都传送到myservlet".查看之前的帖子(例如，根映射此处和此处，或 url 重写此处)，我以为我想通了，但它不起作用.

Since the service I want to process may send requests to the root, I would like to map my servlet to be the default servlet, thereby receiving any request that does not have an explicit servlet mapping. Assume my servlet's name is "myservlet", and is running along side of another servlet "foo", I expect all requests in the form of http://mycompany.com/foo/... to be delivered to foo, and everything else (e.g., /, /bar/..., /myservlet/...) to "myservlet". Looking at earlier posts (eg., root mapping here and here, or url rewriting here), I thought I figured it out, but it does not work.

这是我的 web.xml:

<web-app>
  <servlet>
    <servlet-name>ProxyServlet</servlet-name>
    <servlet-class>com.mycompany.MyProxyServlet</servlet-class>
    <load-on-startup>1</load-on-startup>
  </servlet>

  <servlet-mapping>
    <servlet-name>ProxyServlet</servlet-name>
    <url-pattern>/*</url-pattern>
  </servlet-mapping>
</web-app>

在上面的 web.xml 中，我尝试了 url-pattern

In the above web.xml, for url-pattern I tried

"/" and "/*" and empty (i.e., <url-pattern></url-pattern>), all behave the same -->
    Requests to root (/)goes to tomcat's default servlet
    Requests to /myservlet/... are handled by "myservlet"
    Requests to /fubar/... are always 404

有没有办法将我的 servlet 设为默认值.即，任何没有专门映射到 servlet 的请求都会出现在我的身上(甚至可以接受所有请求，因为我可以将这个 servlet 部署在它自己的容器中).以防万一，我在 Ubuntu 12.10 上使用 Tomcat 7.0.30.

Is there a way of turning my servlet to be the default. I.e., any request that does not map specifically to a servlet comes to mine (it is even acceptable to receive all requests, since I can deploy this servlet in its own container). In case it matters, I am using Tomcat 7.0.30 on Ubuntu 12.10.

将特定 servlet 映射为 Tomcat 中的默认 servlet [英] Mapping a specific servlet to be the default servlet in Tomcat

问题描述

推荐答案

Chapter 12. Mapping Requests to Servlets

12.2 Specification of Mappings

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将特定 servlet 映射为 Tomcat 中的默认 servlet [英] Mapping a specific servlet to be the default servlet in Tomcat

问题描述

推荐答案

Chapter 12. Mapping Requests to Servlets

12.2 Specification of Mappings

相关文章

Java开发最新文章

热门教程

热门工具

登录 关闭

登录关闭