使用 curl 命令行将多个文件上传到 php 服务器 [英] upload multiple files to php server using curl command line

问题描述

我需要使用 curl 命令行实用程序将多个文件上传到服务器.对于单个文件，我使用没有问题:

I need to upload multiple files to a server using the curl command line utility. for a single file I have no problem using:

curl -F "image=@file1.gif"   http://localhost:8888/web/Upload.php

我将如何处理多个文件，以便 php 变量 $_FILES["image"]["error"] 返回一个数组?

how would I do this with more than one file so that the php variable $_FILES["image"]["error"] would return an array?

我试过了

curl -F "image=@file1.gif" -F "image=@file2.gif"  http://localhost:8888/web/Upload.php
curl -F "image=@file1.gif,image=@file2.gif"  http://localhost:8888/web/Upload.php

但这些都是暗中刺伤.

推荐答案

诀窍是命名文件上传参数唯一.

The trick is to name the file uploading parameters unique.

curl -F "image=@file1.gif" -F "image2=@file2.gif"  http://localhost:8888/web/Upload.php

这将在 $_FILES 超全局变量中显示为 $_FILES['image'] 和 $_FILES['image2'].

This will show up in the $_FILES superglobal as $_FILES['image'] and $_FILES['image2'].

要将文件分组到一个 $_FILES 索引下，您需要将参数命名为数组:

To make the files grouped under one $_FILES index you need to name the parameters as arrays:

curl -F "image[]=@file1.gif" -F "image[]=@file2.gif"  http://localhost:8888/web/Upload.php

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