如何编写一个捕获所有异常的 `try`/`except` 块? [英] How can I write a `try`/`except` block that catches all exceptions?

问题描述

如何编写一个try/except 块来捕获所有异常?

How can I write a try/except block that catches all exceptions?

推荐答案

你可以，但你可能不应该:

You can but you probably shouldn't:

try:
    do_something()
except:
    print("Caught it!")

但是，这也会捕获像 KeyboardInterrupt 这样的异常，而您通常不希望那样，对吗?除非您立即重新提出异常 - 请参阅以下示例来自文档:

However, this will also catch exceptions like KeyboardInterrupt and you usually don't want that, do you? Unless you re-raise the exception right away - see the following example from the docs:

try:
    f = open('myfile.txt')
    s = f.readline()
    i = int(s.strip())
except IOError as (errno, strerror):
    print("I/O error({0}): {1}".format(errno, strerror))
except ValueError:
    print("Could not convert data to an integer.")
except:
    print("Unexpected error:", sys.exc_info()[0])
    raise

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