如何从孙子类调用超级方法? [英] How to call super method from grandchild class?

问题描述

我正在处理一些具有 3 级类继承的代码.从最低级别的派生类开始，调用方法 2 的语法是什么?一个 super.super 电话?中间"类没有实现我需要调用的方法.

I am working with some code that has 3 levels of class inheritance. From the lowest level derived class, what is the syntax for calling a method 2 levels up the hierarchy, e.g. a super.super call? The "middle" class does not implement the method I need to call.

推荐答案

好吧，这是一种方法:

class Grandparent(object):
    def my_method(self):
        print "Grandparent"

class Parent(Grandparent):
    def my_method(self):
        print "Parent"

class Child(Parent):
    def my_method(self):
        print "Hello Grandparent"
        Grandparent.my_method(self)

也许不是你想要的，但除非我弄错了，否则它是最好的 python.您所问的问题听起来很反 Python，您必须解释为什么要这样做，以便我们为您提供快乐的 Python 做事方式.

Maybe not what you want, but it's the best python has unless I'm mistaken. What you're asking sounds anti-pythonic and you'd have to explain why you're doing it for us to give you the happy python way of doing things.

另一个例子，也许你想要什么(来自你的评论):

Another example, maybe what you want (from your comments):

class Grandparent(object):
    def my_method(self):
        print "Grandparent"

class Parent(Grandparent):
    def some_other_method(self):
        print "Parent"

class Child(Parent):
    def my_method(self):
        print "Hello Grandparent"
        super(Child, self).my_method()

如你所见，Parent 没有实现 my_method 但 Child 仍然可以使用 super 来获取 的方法Parent看到"，即Grandparent的my_method.

As you can see, Parent doesn't implement my_method but Child can still use super to get at the method that Parent "sees", i.e. Grandparent's my_method.

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