如何使用 PIL 读取原始图像? [英] How to read a raw image using PIL?

问题描述

我有一个原始图像，其中每个像素对应一个 16 位无符号整数.我正在尝试使用 PIL Image.fromstring() 函数进行读取，如下面的代码所示:

I have a raw image where each pixel corresponds to a 16 bits unsigned integer. I am trying to read using the PIL Image.fromstring() function as in the following code:

if __name__ == "__main__":
    if (len(sys.argv) != 4):
        print 'Error: missing input argument'
        sys.exit()

    file = open(sys.argv[1], 'rb')
    rawData = file.read()
    file.close()

    imgSize = (int(sys.argv[2]), int(sys.argv[3]))

    # Use the PIL raw decoder to read the data.
    #   - the 'F;16' informs the raw decoder that we are reading a little endian, unsigned integer 16 bit data.
    img = Image.fromstring('L', imgSize, rawData, 'raw', 'F;16')

    im.save('out.png')

PIL 文档告知 fromstring() 函数的第一个参数是模式".但是，查看文档和谷歌搜索我无法找到有关该参数真正含义的详细信息(我相信它与色彩空间或类似的东西有关).有谁知道在哪里可以找到有关 fromstring() 函数以及 mode 参数含义的更详细参考资料?

The PIL documentation informs that the first argument of the fromstring() function is 'mode'. However, looking at the documentation and googling I wasn't able to find details about what that argument really means (I believe that it is related to the color space or something like that). Does anyone knows where I can find a more detailed reference about the fromstring() function and what the mode argument means?

推荐答案

具体文档在 http://effbot.org/imagingbook/concepts.htm:

图像的模式定义了类型和图像中像素的深度.这当前版本支持以下标准模式:

Mode

The mode of an image defines the type and depth of a pixel in the image. The current release supports the following standard modes:

• 1(1 位像素，黑白，每字节一个像素存储)
• L(8 位像素，黑白)
• P(8 位像素，使用调色板映射到任何其他模式)
• RGB(3x8 位像素，真彩色)
• RGBA(4x8 位像素，带透明蒙版的真彩色)
• CMYK(4x8 位像素，分色)
• YCbCr(3x8 位像素，彩色视频格式)
• I(32 位有符号整数像素)
• F(32 位浮点像素)

PIL 还提供有限的支持一些特殊模式，包括 LA(L带 alpha), RGBX (真彩色带padding) 和 RGBa (真彩色预乘 alpha).

PIL also provides limited support for a few special modes, including LA (L with alpha), RGBX (true colour with padding) and RGBa (true colour with premultiplied alpha).

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