如何返回 DOMDocument 的外部 html? [英] How to return outer html of DOMDocument?

问题描述

我正在尝试替换字符串中的视频链接 - 这是我的代码:

I'm trying to replace video links inside a string - here's my code:

$doc = new DOMDocument();
$doc->loadHTML($content);
foreach ($doc->getElementsByTagName("a") as $link) 
{
    $url = $link->getAttribute("href");
    if(strpos($url, ".flv"))
    {
        echo $link->outerHTML();
    }
}

不幸的是，当我尝试获取像 <a href='http://www.myurl.com 这样的完整超链接的 html 代码时，outerHTML 不起作用/video.flv'>

Unfortunately, outerHTML doesn't work when I'm trying to get the html code for the full hyperlink like <a href='http://www.myurl.com/video.flv'></a>

任何想法如何实现这一目标?

Any ideas how to achieve this?

推荐答案

从 PHP 5.3.6 开始，您可以将节点传递给 saveHtml，例如

As of PHP 5.3.6 you can pass a node to saveHtml, e.g.

$domDocument->saveHtml($nodeToGetTheOuterHtmlFrom);

以前版本的 PHP 没有实现这种可能性.您必须使用 saveXml()，但这会创建符合 XML 的标记.对于 元素，这应该不是问题.

Previous versions of PHP did not implement that possibility. You'd have to use saveXml(), but that would create XML compliant markup. In the case of an <a> element, that shouldn't be an issue though.

参见 http://blog.gordon-oheim.biz/2011-03-17-The-DOM-Goodie-in-PHP-5.3.6/

这篇关于如何返回 DOMDocument 的外部 html?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！