如何在 PHP 脚本中将参数从命令行传递到 $_POST? [英] How can I pass parameters from the command line to $_POST in a PHP script?

问题描述

我知道这听起来有点奇怪，但我需要将一些参数传递给 $_POST 数组.类似于 Apache 或任何其他网络服务器的方式.

I know this could sound a little weird, but I need to pass some parameters to the $_POST array. Similar to the way Apache does it, or any other web server.

不幸的是，我在任何地方都找不到 libapache2-mod-php5 用于我的 Ubuntu 安装.

Unfortunately I couldn't find libapache2-mod-php5 anywhere for my Ubuntu installation.

推荐答案

这并不容易.您可以调用 php-cgi 二进制文件并通过管道将假 POST 请求传入.但您需要设置大量 CGI 环境变量:

That's not easily doable. You can invoke the php-cgi binary and pipe a fake POST request in. But you'll need to set up a whole lot of CGI environment variables:

echo 'var1=123&var2=abc' | REQUEST_METHOD=POST  SCRIPT_FILENAME=script.php REDIRECT_STATUS=CGI CONTENT_TYPE=application/www-form-urlencoded php-cgi 

注意:不足，不能那样工作.但类似的事情...

Note: Insufficient, doesn't work like that. But something like that...

如果您只是修补脚本，并让它从预定义的环境变量中加载 $_POST 数组，那肯定会更容易.

It's certainly easier if you just patch the script, and let it load the $_POST array from a predefined environment variable.

$_POST = parse_url($_SERVER["_POST"]);

为了简单起见，您可以像 _POST=var=123 php script.php 一样调用它.

Then you can invoke it like _POST=var=123 php script.php for simplicity.

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