在 NSURLRequest 中通过 POST 发送 JSON [英] Sending a JSON via POST in NSURLRequest
问题描述
我在使用 REST API 向服务器发送 JSON 时遇到问题.这是我使用的代码:
I have a problem with sending a JSON to a Server with REST API. This is the code i use:
NSString *jsonPostBody = [NSString stringWithFormat:@"'json' = '{"user":{"username":"
""%@""
","password":"
""%@""
"}}'",
[username stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding],
[password stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]];
NSData *postData = [jsonPostBody dataUsingEncoding:NSUTF8StringEncoding allowLossyConversion:YES];
NSString *apiPathParams = [NSString stringWithFormat:@"%@",
@"getUser"
];
NSURL *url = [NSURL URLWithString:[[apiPath retain] stringByAppendingString:apiPathParams]];
NSMutableURLRequest* request = [NSMutableURLRequest requestWithURL:url
cachePolicy:NSURLRequestReloadIgnoringLocalCacheData
timeoutInterval:180.0];
[request setHTTPMethod:@"POST"];
[request setHTTPBody:postData];
NSString* postDataLengthString = [[NSString alloc] initWithFormat:@"%d", [postData length]];
[request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[request setValue:postDataLengthString forHTTPHeaderField:@"Content-Length"];
[self internalRequest:request];
如果它是 html 表单,API 会是什么样子:
This is what the API would look like, if it was a html form:
<form method="post" action="someAPI-URL">
<input name="json" value="{"user":...}" />
</form>
这是我将 POST 数据添加到请求时的样子:
This is what my POST Data looks like when i add it to the request:
json={"user":{"username":"someUser","password":"somePassword"}}
出于某种原因,我不知道 POST 数据没有到达服务器.我对 dataString 的格式做错了吗?我必须如何准确地格式化我的 dataString 以便它匹配上面显示的表单将传递到服务器的字符串?
For a reason I don't know the POST Data does not arrive at the server. Have i done something wrong with the formatting of the dataString? How exactly must i format my dataString so that it matches the String a form as shown above would deliver to the server?
任何帮助将不胜感激.
附言我宁愿不使用 ASIHttpRequest,因为我从其他人那里接手了这个项目,除了这个 post-request 之外,所有其他请求都可以正常工作.因此,将整个批量更改为其他连接框架将非常耗时.
P.S. I would rather not use ASIHttpRequest, since i took over the project from somebody else an every other request works fine, except this post-request. So changing this whole bulk to an other connection framework would be very time consuming.
这里是internalRequest方法的源码
Here is the internalRequest Method's sourcecode
NSURLConnection *connection = [[NSURLConnection alloc] initWithRequest:req delegate:self];
NSMutableDictionary *di = [NSMutableDictionary dictionaryWithObject:[[NSMutableData alloc] init] forKey:@"receivedData"];
[di setObject:[NSString stringWithFormat:@"%i",identifier] forKey:@"identifier"];
if (delegate == nil)
{
delegate = self;
}
[di setObject:delegate forKey:@"delegate"];
CFDictionaryAddValue(connectionToInfoMapping, connection, di)
推荐答案
因为你尝试提交一个像
json={"user":{"username":"%@","password":"%@"}}
,
这个例子完全有资格导致混乱.
this example is fully qualified to end up in confusion.
它混合了 application/x-www-form-urlencoded
用于整个 body 和 application/json
用于值.
It's a mixture of application/x-www-form-urlencoded
for the whole body and application/json
for the value.
也许可以解决这个问题:
您可能需要调整该 HTTP 标头:
You'll probably need to adjust that HTTP header:
[request setValue:@"application/x-www-form-urlencoded"
forHTTPHeaderField:@"Content-Type"];
由于 HTTP 正文的 JSON 部分(值)的编码:
due to an encoding of the JSON part (value) of the HTTP body:
[request setHTTPBody:[[jsonPostBody stringByAddingPercentEscapesUsingEncoding:NSASCIIStringEncoding]
dataUsingEncoding:NSUTF8StringEncoding
allowLossyConversion:YES]];
其中 stringByAddingPercentEscapesUsingEncoding
是 PHP 等效 urlencode
的目标 c jabberwocky.
where stringByAddingPercentEscapesUsingEncoding
is objective c jabberwocky for the PHP equivalent urlencode
.
HTH
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