什么是Java 8个流API相当于LINQ加入？ [英] What is the Java 8 Stream API equivalent for LINQ Join?

问题描述

在C＃/。NET有可能加盟的IEnumerable序列与在SQL扩展方法Enumerable.JoinJOIN ... ON'的方式。

In C#/.Net it is possible to join IEnumerable sequences with the extension method Enumerable.Join in a SQL 'JOIN ... ON' way.

有没有在Java中8（流API）相似的地方？或者有什么是模拟Enumerable.Join最好的方法是什么？

Is there something similar in Java 8 (Stream API)? Or what is the best way to simulate Enumerable.Join?

请参阅： https://msdn.microsoft.com/en -us /库/ bb534675％28V = VS.100％29.aspx

推荐答案

我还没有发现任何现有的相当，但低于方法应该工作：

I haven't found any existing equivalent, but the below method should work:

public static <Outer, Inner, Key, Result> Stream<Result> join(
        Stream<Outer> outer, Stream<Inner> inner,
        Function<Outer, Key> outerKeyFunc,
        Function<Inner, Key> innerKeyFunc,
        BiFunction<Outer, Inner, Result> resultFunc) {

    //Collect the Inner values into a list as we'll need them repeatedly
    List<Inner> innerList = inner.collect(Collectors.toList());

    //matches will store the matches between inner and outer
    final Map<Outer, List<Inner>> matches = new HashMap<>();

    //results will be used to collect the results in
    final List<Result> results = new ArrayList<>();


    outer.forEach(o -> innerList
            .stream()
            //Filter to get those Inners for which the Key equals the Key of this Outer
            .filter(i -> innerKeyFunc.apply(i).equals(outerKeyFunc.apply(o)))
            .forEach(i -> {
                if (matches.containsKey(o)) {
                    //This Outer already had matches, so add this Inner to the List
                    matches.get(o).add(i);
                } else {
                    //This is the first Inner to match this Outer, so create a List
                    List<Inner> list = new ArrayList<>();
                    list.add(i);
                    matches.put(o, list);
                }
            }));

    matches.forEach((out, in) -> in.stream()
            //Map each (Outer, Inner) pair to the appropriate Result...
            .map(i -> resultFunc.apply(out, i))
            //...and collect them
            .forEach(res -> results.add(res)));

    //Return the result as a Stream, like the .NET method does (IEnumerable)
    return results.stream();
}

我只用下面的输入做的code简短的测试：

I only did a brief test of the code using the following inputs:

public static void main(String[] args) {
    Stream<String> strings = Arrays.asList("a", "b", "c", "e", "f", "d").stream();
    Stream<Integer> ints = Arrays.asList(1, 2, 3, 6, 5, 4).stream();
    Stream<String> results = join(strings, ints, 
            Function.identity(),
            str    -> Integer.parseInt(str, 16) - 9, 
            (o, i) -> "Outer: " + o + ", Inner: " + i);
    results.forEach(r -> System.out.println(r));
}

• 的 INT 是自己的钥匙，所以没有转化
• 的字符串映射到 INT 根据自己的十六进制值S - 9
• （元素相匹配，如果 INT 值相等时，按默认值）
• 配对放入一个字符串
• The ints are their own keys, so no transformation
• The Strings are mapped to ints according to their hex value - 9
• (The elements match if the int values are equal, as per default)
• Matching pairs are put into a String

下面的（正确的）打印结果：

The following (correct) results are printed:

Outer: a, Inner: 1
Outer: b, Inner: 2
Outer: c, Inner: 3
Outer: d, Inner: 4
Outer: e, Inner: 5
Outer: f, Inner: 6

更深入的测试将是必要的，当然，但我相信这个实现是正确的。这也许可以更有效的为好，我很开放的建议。

More in-depth testing will be needed, of course, but I believe this implementation to be correct. It could probably be more efficient as well, I'm open to suggestions.

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