Firebase DatabaseException:无法将 java.lang.Long 类型的值转换为 String [英] Firebase DatabaseException: Failed to convert value of type java.lang.Long to String

问题描述

com.google.firebase.database.DatabaseException:转换失败java.lang.Long 类型的值转为 String

com.google.firebase.database.DatabaseException: Failed to convert value of type java.lang.Long to String

是我在按照文档尝试将数据检索到对象以供使用时不断遇到的错误.

is the error I keep getting when following the docs in attempting to retrieve data to an object for use.

这是我的对象模型

public class User {

    private String tour_director_key;
    private String last_name;
    private String location_latitude;
    private String tour_id;
    private String photo;
    private String tour_director_name;
    private String middle_name;
    private String location_longitude;
    private String passenger_id;
    private long location_updated;
    private String tour_director;
    private String email;
    private String first_name;
    private String mobile_phone;
    private String td_id;

    public User() {
        // empty default constructor, necessary for Firebase to be able to deserialize users
    }

    public String getTour_director_key() {
        return tour_director_key;
    }
    public String getLast_name() {
        return last_name;
    }
    public String getLocation_latitude() {
        return location_latitude;
    }
    public String getTour_id() {
        return tour_id;
    }
    public String getPhoto() {
        return photo;
    }
    public String getTour_director_name() {
        return tour_director_name;
    }
    public String getMiddle_name() {
        return middle_name;
    }
    public String getLocation_longitude() {
        return location_longitude;
    }
    public String getPassenger_id() { return passenger_id; }
    public String getMobile_phone() { return mobile_phone; }
    public long getLocation_updated() {
        return location_updated;
    }
    public String getTour_director() {
        return tour_director;
    }
    public String getEmail() {
        return email;
    }
    public String getFirst_name() {
        return first_name;
    }
    public String getTd_id() { return td_id; }

}

用户的 firebase 数据:

Data on firebase for user:

最后是代码 &我得到错误的那一行被注释了.

and finally the code & line I get the error on is commented.

  Query userDataQuery = Constants.USER_REF.orderByKey().equalTo(mUserId);

  userDataQuery.addValueEventListener(new ValueEventListener() {
      @Override
      public void onDataChange(DataSnapshot dataSnapshot) {
         for (DataSnapshot postSnapshot : dataSnapshot.getChildren()) {
             //// ERROR COMES FROM THE LINE BELOW ////
             User currentUser = postSnapshot.getValue(User.class);
             Log.i("THE_CURRENT_USER:::", currentUser.toString());
             Log.i("THE_USERS_EMAIL:::", currentUser.getEmail());

             ...

完整的堆栈跟踪:

FATAL EXCEPTION: main
Process: app.timto.co.app, PID: 7453
com.google.firebase.database.DatabaseException: Failed to convert value of type java.lang.Long to String
    at com.google.android.gms.internal.zzaln.zzcc(Unknown Source)
    at com.google.android.gms.internal.zzaln.zzb(Unknown Source)
    at com.google.android.gms.internal.zzaln.zza(Unknown Source)
    at com.google.android.gms.internal.zzaln.zzb(Unknown Source)
    at com.google.android.gms.internal.zzaln$zza.zze(Unknown Source)
    at com.google.android.gms.internal.zzaln$zza.zzcc(Unknown Source)
    at com.google.android.gms.internal.zzaln.zzd(Unknown Source)
    at com.google.android.gms.internal.zzaln.zzb(Unknown Source)
    at com.google.android.gms.internal.zzaln.zza(Unknown Source)
    at com.google.firebase.database.DataSnapshot.getValue(Unknown Source)
    at app.timto.co.app.AttendanceActivity$1$1.onDataChange(AttendanceActivity.java:112)
    at com.google.android.gms.internal.zzaie.zza(Unknown Source)
    at com.google.android.gms.internal.zzaje.zzcta(Unknown Source)
    at com.google.android.gms.internal.zzajh$1.run(Unknown Source)
    at android.os.Handler.handleCallback(Handler.java:739)
    at android.os.Handler.dispatchMessage(Handler.java:95)
    at android.os.Looper.loop(Looper.java:148)
    at android.app.ActivityThread.main(ActivityThread.java:5417)
    at java.lang.reflect.Method.invoke(Native Method)
    at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:726)
    at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:616)

推荐答案

问题是您将属性mobile_phone"创建为字符串，而在 Firebase 上它是 Long 类型.

The problem is that you are creating the property "mobile_phone" as a String and on Firebase it is a Long type.

变化:

private String mobile_phone;

致:

private Long mobile_phone;

这篇关于Firebase DatabaseException:无法将 java.lang.Long 类型的值转换为 String的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！