Swift - 如何将“shouldChangeTextInRange"与 Firebase 结合使用进行实时搜索? [英] Swift - How Can I use 'shouldChangeTextInRange' with Firebase for real time searching?

问题描述

我想知道如何使用 shouldChangeTextInRange 创建 Firebase 匹配Regex 查询 和列出当前结果.

我之前在 Parse 中做过，用于在 Parse Cloud 中搜索用户名或用户全名.如果有人为我指明在 Firebase 中实现它的道路，那就太好了.

//搜索更新func searchBar(searchBar: UISearchBar, shouldChangeTextInRange range: NSRange, replacementText text: String) ->布尔{//根据用户名查找让 usernameQuery = PFQuery(className: "_User")usernameQuery.whereKey("username",matchesRegex: "(?i)" + searchBar.text!)usernameQuery.findObjectsInBackgroundWithBlock { (objects:[PFObject]?, error:NSError?) ->作废如果错误 == 零 {//如果根据用户名列中输入的文本没有找到对象，则按全名查找如果对象！.isEmpty {让 fullnameQuery = PFUser.query()fullnameQuery?.whereKey("fullname",matchesRegex:"(?i)" + self.searchBar.text!)fullnameQuery?.findObjectsInBackgroundWithBlock({ (objects:[PFObject]?, error:NSError?) -> Void in如果错误 == 零 {//清理self.usernameArray.removeAll(keepCapacity: false)self.avaArray.removeAll(keepCapacity: false)//找到相关对象对于对象中的对象！{self.usernameArray.append(object.objectForKey("username") as!String)self.avaArray.append(object.objectForKey("avatar") as!PFFile)}//重新加载self.tableView.reloadData()}})}}//清理self.usernameArray.removeAll(keepCapacity: false)self.avaArray.removeAll(keepCapacity: false)//找到相关对象对于对象中的对象！{self.usernameArray.append(object.objectForKey("username") as!String)self.avaArray.append(object.objectForKey("avatar") as!PFFile)}//重新加载self.tableView.reloadData()}返回真}

<块引用>

更新 1:

我无法使用相同的父名称来执行此操作，snap.value 没有给我响应，甚至无法编译.所以我尝试做两个单独的父节点:firebase 屏幕截图链接

我在 xcode 控制台上收到 indexOn 安全警告 对于每个字母笔划 first_name 子节点:

<块引用>

[Firebase] 使用未指定的索引.考虑将/people_spell 的 ".indexOn": "first_name/T" 添加到您的安全规则中以获得更好的性能

[Firebase] 使用未指定的索引.考虑将/people_spell 的 ".indexOn": "first_name/Te" 添加到您的安全规则中以获得更好的性能

...更多次

我已经尝试过这些安全规则，但没有解决这些问题.它不包含每个子节点.我该如何提供?

"people_spell": {".read": "auth !== null",".write": "auth !== null",".indexOn": "first_name"},人们": {".read": "auth !== null",".write": "auth !== null",".indexOn": "first_name"}

我正在使用这些代码行:

let peopleSpellRef = Firebase(url: "https://sampleproject.firebaseio.com/people_spell")让 peopleRef = Firebase(url: "https://sampleproject.firebaseio.com/people")func searchBar(searchBar: UISearchBar, shouldChangeTextInRange range: NSRange, replacementText text: String) ->布尔{self.usernameArray.removeAll(keepCapacity: false)peopleSpellRef.queryOrderedByChild("first_name/(searchBar.text!)").queryEqualToValue(true).observeEventType(.Value, withBlock: { 快照输入让枚举数 = snapshot.children而 let rest = enumerator.nextObject() as?FDataSnapshot {peopleRef.childByAppendingPath("(rest.key)").observeEventType(.Value, withBlock: { snapshot inself.usernameArray.removeAll(keepCapacity: false)让 str: String = (snapshot.value.objectForKey("first_name")) as!(细绳)打印(字符串)self.usernameArray.append(str)self.userkeyArray.append(snapshot.key)self.tableView.reloadData()})}self.usernameArray.removeAll(keepCapacity: false)self.tableView.reloadData()})返回真}

解决方案

这不是 Firebase 的工作方式，您不能直接在 Firebase 中对子字符串进行实时搜索".但是，您可以格式化要搜索的 Firebase 数据，还有其他几种方法也可以实现目标.

一个很简单:将您的数据从 Firebase 加载到一个数组中，然后通过该数组进行 NSPredicate 搜索(或其他方法).

另一个是查询完整字符串很容易；只要将文本分解为您要搜索的块:

人人_0名字:泰德"姓氏:史崔克"位置:坐下面向前方"人_1名字:泰迪"

您可以在 first_name 中搜索Ted"或在 last_name 中搜索Stryker"，但不能在 position 中搜索front".

现在解决方法并记住磁盘空间很便宜.

可以创建一个节点，让您以多种方式搜索内容

人人_0first_name//名字是上面的TedT:真的特:真的泰德:真的ed:真的d: 真的e: 真的人_1first_name//名字是上面的泰迪T:真的特:真的泰德:真的等等

通过这个结构，我们可以找到所有以 Ted 开头的名字

 peopleRef.queryOrderedByChild("first_name/Ted").queryEqualToValue(true).observeEventType(.Value, withBlock: { 快照输入对于快照中的孩子.孩子{打印(子值)}})

可以进行其他搜索；搜索所有包含 e 或 Te 等的名字.

如果这纯粹是您正在搜索以在文本字段中执行自动填充的情况(例如)，逐个按键地对 firebase 进行 ping 操作是行不通的.

将数据从 Firebase 加载到数组或字典(或其他)中可能是您​​最好的解决方案.

I wonder that how creating Firebase matchesRegex query and listing current results using shouldChangeTextInRange.

I have did it before in Parse for searching username or user fullname in Parse Cloud. If someone shed light my path to do it in Firebase, it would be great.

// search updated
func searchBar(searchBar: UISearchBar, shouldChangeTextInRange range: NSRange, replacementText text: String) -> Bool {

    // find by username
    let usernameQuery = PFQuery(className: "_User")
    usernameQuery.whereKey("username", matchesRegex: "(?i)" + searchBar.text!)
    usernameQuery.findObjectsInBackgroundWithBlock { (objects:[PFObject]?, error:NSError?) -> Void in

        if error == nil {

            // if no objects are found according to entered text in username column, find by fullname
            if objects!.isEmpty {

                let fullnameQuery = PFUser.query()
                fullnameQuery?.whereKey("fullname", matchesRegex: "(?i)" + self.searchBar.text!)
                fullnameQuery?.findObjectsInBackgroundWithBlock({ (objects:[PFObject]?, error:NSError?) -> Void in

                    if error == nil {

                        // clean up
                        self.usernameArray.removeAll(keepCapacity: false)
                        self.avaArray.removeAll(keepCapacity: false)

                        // found related objects
                        for object in objects! {
                            self.usernameArray.append(object.objectForKey("username") as! String)
                            self.avaArray.append(object.objectForKey("avatar") as! PFFile)
                        }

                        // reload
                        self.tableView.reloadData()

                    }

                })

            }

        }

        // clean up
        self.usernameArray.removeAll(keepCapacity: false)
        self.avaArray.removeAll(keepCapacity: false)

        // found related objects
        for object in objects! {
            self.usernameArray.append(object.objectForKey("username") as! String)
            self.avaArray.append(object.objectForKey("avatar") as! PFFile)
        }

        // reload
        self.tableView.reloadData()

    }

    return true

}

Update 1:

I couldn't do it using same parent name, snap.value didn't give me response, even not compile. So I have tried to do two separate parent node like that: firebase screen shot link

I'm getting indexOn security warning for each letter stroke first_name subnodes on xcode console:

[Firebase] Using an unspecified index. Consider adding ".indexOn": "first_name/T" at /people_spell to your security rules for better performance

[Firebase] Using an unspecified index. Consider adding ".indexOn": "first_name/Te" at /people_spell to your security rules for better performance

... much more times

I have tried these security rules it didn't solve these problems. It doesn't encompass each subnodes. How Can I provide this?

"people_spell": {
      ".read": "auth !== null",
      ".write": "auth !== null",
      ".indexOn": "first_name"
    },
"people": {
      ".read": "auth !== null",
      ".write": "auth !== null",
      ".indexOn": "first_name"
}

I'm using these lines of codes:

let peopleSpellRef = Firebase(url: "https://sampleproject.firebaseio.com/people_spell")
let peopleRef = Firebase(url: "https://sampleproject.firebaseio.com/people")

func searchBar(searchBar: UISearchBar, shouldChangeTextInRange range: NSRange, replacementText text: String) -> Bool {

   self.usernameArray.removeAll(keepCapacity: false)

   peopleSpellRef.queryOrderedByChild("first_name/(searchBar.text!)").queryEqualToValue(true)
    .observeEventType(.Value, withBlock: { snapshot in

        let enumerator = snapshot.children
        while let rest = enumerator.nextObject() as? FDataSnapshot {

            peopleRef.childByAppendingPath("(rest.key)").observeEventType(.Value, withBlock: { snapshot in

                self.usernameArray.removeAll(keepCapacity: false)

                let str: String = (snapshot.value.objectForKey("first_name")) as! (String)
                print(str)
                self.usernameArray.append(str)
                self.userkeyArray.append(snapshot.key)

                self.tableView.reloadData()
            })
        }


        self.usernameArray.removeAll(keepCapacity: false)
        self.tableView.reloadData()

    })

return true
}

解决方案

This is not how Firebase works and you can't directly do a 'real time search' in Firebase for a substring. But, you can format your Firebase data to be searched and there are a couple of other methods which will also accomplish the goal.

One is straightforward: load your data from Firebase into an array and NSPredicate search (or other methods) through the array.

Another is that query'ing for full strings is easy; as long as the text is broken up into the chunks you want to search for:

people
  person_0
    first_name: "Ted"
    last_name: "Stryker"
    position: "sitting down and facing front"
  person_1
    first_name: "Teddy"

You can search for 'Ted' in first_name or 'Stryker' in last_name but you cannot search for 'front' in position.

Now the workaround and keep in mind disk space is cheap.

A node can be created that will let you search for stuff in a variety of ways

people
  person_0
   first_name //First name is Ted from above
    T: true
    Te: true
    Ted: true
    ed: true
    d: true
    e: true
  person_1
   first_name  //First name is Teddy from above
    T: true
    Te: true
    Ted: true
    etc

With this structure we can find all first names that start with Ted

    peopleRef.queryOrderedByChild("first_name/Ted").queryEqualToValue(true)
         .observeEventType(.Value, withBlock: { snapshot in

        for child in snapshot.children {
          print(child.value)  
        }
    })

Other searches can be performed; searching for all first names that contain e or Te etc.

If this is purely a situation where you are searching to perform an autofill in a text field (for example) pinging firebase on a keystroke by keystroke basis isn't going to work well.

Loading the data from Firebase into an array, or dictionary (or whatever) will probably be your best solution.

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